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Vilka [71]
3 years ago
8

You plan to paint the outside of this garage, including the roof. Which calculation will help you best decide how much paint you

will need? (Omit the floor of the garage in your calculation.) Add the areas of 9 rectangles and 2 triangles. Add the areas of 6 rectangles and 2 triangles. Add the volumes of 1 rectangular prism and 1 triangular prism. Add the perimeters of 4 rectangles and 2 triangles.
Mathematics
2 answers:
Tju [1.3M]3 years ago
7 0

Answer:

add the areas of 6 rectangles and 2 triangles

Step-by-step explanation:

QveST [7]3 years ago
5 0
The four walls will be four rectangles.
The roof will be two rectangles.
The ends holding up the roof will be two triangles.

The 2nd selection is appropriate (areas of 6 rectangles + 2 triangles).

_____
Yes, you're trying to find the volume of paint, but paint is sold in terms of the number of square feet (area) it covers. Rarely do we concern ourselves with computing paint volume from the thickness of the film covering the area. Certainly, the volume of paint is substantially less than the volume of the walls or the entire garage.
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hichkok12 [17]

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Step-by-step explanation:

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3 years ago
Use a power series to approximate the value of the integral with an error of less than 0.0001. (Round your answer to four decima
otez555 [7]

Answer:

The answer is "0.9461"

Step-by-step explanation:

Given:

\int^1_0 \frac{sin(x)}{x} dx\\\\

\int^1_0 \frac{sin(x)}{x} dx\\\\ ≈\sum^2_{n=0}\frac{(-1)^n x^{2n+1} (-1)^n (x-1)^n}{(2n + 1)!}

\therefore

\to \sin x = \sum^{\infty}_{n=0} (-1)^n\frac{x^{(2n+1)}}{(2n + 1)!}

\because \\\\  \to \frac{\sin x}{x} =\sum^{\infty}_{n=0} (-1)^n \frac{x^{2n+1-1}}{(2n+1)!}\\

           =\sum^{\infty}_{n=0} (-1)^n \frac{x^{2n}}{(2n+1)!}

The value is in between 0 and 1 then:

 \to \int^1_0 \frac{sin(x)}{x} = =\sum^{2}_{n=0}  \frac{(-1)^n}{ (2n+1) (2n+1)!}

The above-given series is an alternative series, and it will give an error, when the nth term is bounded by its absolute value, that can be described as follows:

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So,

\int^1_0 \frac{sin(x)}{x} dx\\\\ ≈1 - \frac{1}{3 \cdot 3!}+\frac{1}{5 \cdot 5!}\\\\

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Answer:

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