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marissa [1.9K]
1 year ago
14

How many milliliters of

" class="latex-formula"> gas at STP are required to fully hydrogenate 1.68 g of C_{6} H_{8}N_{2} (adiponitrile) according to the following hydrogenation reaction scheme?
C_{6}H_{8}N_{2}(l) + 4H_{2}(g) → C_{6} H_{16}N_{2}(s)
Chemistry
1 answer:
adoni [48]1 year ago
6 0

Answer:

The answer is

21.5 L

.

So, start with the balanced chemical equation for the decomposition of hydrochloric acid

2

HCl

→

H

2

+

Cl

2

Notice that you have a

2:1

mole ratio between

HCl

and

Cl

2

, which means that every 2 moles of the former will produce 1 mole of the latter. The number of moles of

HCl

you have is.

Explanation:

I don't know if that is but I try my best just correct me if I'm wrong thank you!!

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A pan containing 20.0 grams of water was allowed to cool from a temperature of 95.0 °C. If the amount of heat released is 1,200
34kurt

Answer:

81 °C

Explanation:

This is a calorimetry question so a few things you will need for this. The calorimetry equation q=mcΔT & the specific heat of water (4.2J/g•°C). Other definitions are:

q = heat added/released by a sample

m = mass of sample

c=specific heat of sample

ΔT = change in temperature

from here we can rearrange the equation to state:

q/(mc) = ΔT

1200J/((20.0g)(4.2J/g•°C)) = ΔT

14°C = ΔT

If the starting temperature was 95.0°C and we know that the temperature was cooled by 14°C then the final temperature of the water would be 81.

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4 years ago
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Why do two oxygen atoms form a double covalent bond?
elena-s [515]

A lone oxygen atom has 6 electrons in its outer shell which is not very stable, whereas as full octet (8 outer shell electrons) is stable. In order to achieve this two oxygen atoms will share 4 electrons, each contributing 2 electrons. Since these electrons exist within the orbitals of both atoms, to oxygen atoms essentially achieve a full octet.

5 0
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A student determines the molar mass of acetone, CH3COCH3, by the method used in this experiment. She found that the equilibrium
Alexandra [31]

Answer:

(a). 4°C, (b). 2.4M, (c). 11.1 g, (d). 89.01 g, (e). 139.2 g and (f). 58 g/mol.

Explanation:

Without mincing words let's dive straight into the solution to the question.

(a). The freezing point depression can be Determine by subtracting the value of the initial temperature from the final temperature. Therefore;

The freezing point depression = [ 1 - (-3)]° C = 4°C.

(b). The molality can be Determine by using the formula below;

Molality = the number of moles found in the solute/ solvent's weight(kg).

Molality = ( 11.1 / 58) × (1000)/ ( 90.4 - 11.1) = 2.4 M.

(c). The mass of acetone that was in the decanted solution = 11.1 g.

(d). The mass of water that was in the decanted solution = 89.01 g.

(e). 2.4 = x/ 58 × (1000/1000).

x = 2.4 × 58 = 139.2 g.

(f). The molar mass of acetone = (12) + (1 × 3) + 12 + 16 + 12 + (1 x 3) = 58 g/mol.

7 0
3 years ago
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