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marissa [1.9K]
1 year ago
14

How many milliliters of

" class="latex-formula"> gas at STP are required to fully hydrogenate 1.68 g of C_{6} H_{8}N_{2} (adiponitrile) according to the following hydrogenation reaction scheme?
C_{6}H_{8}N_{2}(l) + 4H_{2}(g) → C_{6} H_{16}N_{2}(s)
Chemistry
1 answer:
adoni [48]1 year ago
6 0

Answer:

The answer is

21.5 L

.

So, start with the balanced chemical equation for the decomposition of hydrochloric acid

2

HCl

→

H

2

+

Cl

2

Notice that you have a

2:1

mole ratio between

HCl

and

Cl

2

, which means that every 2 moles of the former will produce 1 mole of the latter. The number of moles of

HCl

you have is.

Explanation:

I don't know if that is but I try my best just correct me if I'm wrong thank you!!

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If 3.00 g of aluminum hydroxide reacts with 1.40 g of sulfuric acid, what is the mass of water produced?
Leokris [45]
The Law of Conservation of Mass states that matter is not created nor destroyed.

Based on this, we can use some addition to find the answer.

3.00 + 1.40 = 4.40 g

Hope this helps :)
4 0
3 years ago
In general, as you move from right to left across a period, the number of valence electrons
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As you move from left to right across a period,the number of valence electrons<span>-increases. </span>
4 0
3 years ago
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An atomic model shows 19 protons, 20 neutrons, and 19 electrons. What is the mass number of the atom?
agasfer [191]
The mass number of the atom is 39
7 0
3 years ago
The composition of a liquid-phase reaction 2A - B was monitored spectrophotometrically. The following data was obtained: t/min 0
o-na [289]

Answer:

1) The order of the reaction is of FIRST ORDER

2)   Rate constant k = 5.667 × 10 ⁻⁴

Explanation:

From the given information:

The composition of a liquid-phase reaction 2A - B was monitored spectrophotometrically.

liquid-phase reaction 2A - B signifies that the reaction is of FIRST ORDER where the rate of this reaction is directly proportional to the concentration of A.

The following data was obtained:

t/min                    0         10         20          30             40          ∞

conc B/(mol/L)    0       0.089    0.153     0.200       0.230    0.312

For  a first order reaction:

K = \dfrac{1}{t} \ In ( \dfrac{C_{\infty} - C_o}{C_{\infty} - C_t})

where :

K = proportionality  constant or the rate constant for the specific reaction rate

t = time of reaction

C_o = initial concentration at time t

C _{\infty} = final concentration at time t

C_t = concentration at time t

To start with the value of t when t = 10 mins

K_1 = \dfrac{1}{10} \ In ( \dfrac{0.312 - 0}{0.312 - 0.089})

K_1 = \dfrac{1}{10} \ In ( \dfrac{0.312 }{0.223})

K_1 =0.03358 \  min^{-1}

K_1 \simeq 0.034 \  min^{-1}

When t = 20

K_2= \dfrac{1}{20} \ In ( \dfrac{0.312 - 0}{0.312 - 0.153})

K_2= 0.05 \times  \ In ( 1.9623)

K_2=0.03371 \ min^{-1}

K_2 \simeq 0.034 \ min^{-1}

When t = 30

K_3= \dfrac{1}{30} \ In ( \dfrac{0.312 - 0}{0.312 - 0.200})

K_3= 0.0333 \times  \ In ( \dfrac{0.312}{0.112})

K_3= 0.0333 \times  \ 1.0245

K_3 = 0.03412 \ min^{-1}

K_3 = 0.034 \ min^{-1}

When t = 40

K_4= \dfrac{1}{40} \ In ( \dfrac{0.312 - 0}{0.312 - 0.230})

K_4=0.025 \times  \ In ( \dfrac{0.312}{0.082})

K_4=0.025 \times  \ In ( 3.8048)

K_4=0.03340 \ min^{-1}

We can see that at the different time rates, the rate constant of k_1, k_2, k_3, and k_4 all have similar constant values

As such :

Rate constant k = 0.034 min⁻¹

Converting it to seconds ; we have :

60 seconds = 1 min

∴

0.034 min⁻¹ =(0.034/60) seconds

= 5.667 × 10 ⁻⁴ seconds

Rate constant k = 5.667 × 10 ⁻⁴

4 0
3 years ago
An unknown compound is found to have a molar mass of 392.16 g/mol. If the empirical formula is C2H5PF2, what is the molecular fo
notsponge [240]

Answer:

C8H20P4F8

Explanation:

Molecular formula is based off a ratio of the molecular formula's molar mass divided by the empirical formula's molar mass.

The molar mass of the empirical formula C2H5PF2 is 98.02g. We find this by adding the molar masses of all elements in the formula, multiplied by their subscripts.

2(12.01) + 5(1.01) + 30.97 + 2(18.99) = 98.02

We then divide the molecular molar mass by the empirical molar mass.

392.16/98.02 = 4

This tells us that the molecular formula has 4 times the mass of the empirical formula. Because mass comes from the elements in the formula, we multiply all the subscripts by 4 to get the molecular formula.

2x4 = 8

5x4 = 20

1x4 = 4

2x4 = 8

So the molecular formula is C8H20P4F8

8 0
3 years ago
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