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2 years ago

6. Calculate the mass of each product when 100.0 g of CuCl react according to the reaction

Chemistry

1 answer:

gavmur [86]2 years ago

6 0

Answer:

67.91 g of CuCl2; 32.09 g of Cu.

Explanation:

The two masses add to 100.0 g, the initial amount of starting material, demonstrating the law of conservation of matter.

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Is fluorine a element, compound or mixture

sp2606 [1]

The answer of the question is mixture

5 0

3 years ago

Read 2 more answers

How many moles of SnCl2 will be produced if 85.3 g of FeCl3 is reacted with an excess of Sn for the following reaction:2 FeCl3(s

Ronch [10]

Answer:

The answer to your question is 0.79 moles of SnCl₂

Explanation:

Data

moles of SnCl₂ = ?

mass of FeCl₃ = 85.3 g

excess Sn

Balanced chemical reaction

2 FeCl₃ + 3 Sn ⇒ 3 SnCl₂ + 2 Fe

Process

1.- Convert the mass of FeCl₃ to moles

Molar mass of FeCl₃ = 56 + (35.5 x 3)

= 56 + 106.5

= 162.5 g

Use proportions to find the moles of FeCl₃

162.5 g -------------------- 1 mol

85.3 g ------------------- x

x = (85.3 x 1) / 162.5

x = 0.525 moles

2.- Find the number of moles SnCl₂

2 moles of FeCl₃ ----------------- 3 moles of SnCl₂

0.525 moles ----------------- x

x = (0.525 x 3) / 2

x = 0.79 moles of SnCl₂

4 0

3 years ago

What is the mass of silver chlorate (191.32 g/mol) that decomposes to release 0.466L of oxygen gas at STP? AgC1036) _AgCl). _026

vesna_86 [32]

Answer : The mass of silver chlorate will be 2.654 grams.

Explanation :

The balanced chemical reaction is,

$2AgClO_3\rightarrow 2AgCl+3O_2$

First we have to calculate the moles of oxygen gas at STP.

As, 22.4 L volume of oxygen gas present in 1 mole of oxygen gas

So, 0.466 L volume of oxygen gas present in $\frac{0.466}{22.4}=0.0208$ mole of oxygen gas

Now we have to calculate the moles of silver chlorate.

From the balanced chemical reaction, we conclude that

As, 3 moles of oxygen produced from 2 moles of silver chlorate

So, 0.0208 moles of oxygen produced from $\frac{2}{3}\times 0.0208=0.01387$ moles of silver chlorate

Now we have to calculate the mass of silver chlorate.

$\text{Mass of }AgClO_3=\text{Moles of }AgClO_3\times \text{Molar mass of }AgClO_3$

Molar mass of silver chlorate = 191.32 g/mole

$\text{Mass of }AgClO_3=0.01387mole\times 191.32g/mole=2.654g$

Therefore, the mass of silver chlorate will be 2.654 grams.

3 0

2 years ago

What is the pH of a<br> 2.5 x 10-5 M solution<br> of HCI?

aalyn [17]

Answer:

The pH of the solution is 4.60.

Explanation:

The pH gives us an idea of the acidity or basicity of a solution. More precisely, it indicates the concentration of H30 + ions present in said solution. The pH scale ranges from 0 to 14: from 0 to 7 corresponds to acid solutions, 7 neutral solutions and between 7 and 14 basic solutions. It is calculated as:

pH = -log (H30 +)

pH= -log (2,5 x 10-5)

7 0

3 years ago

Which of the following statements best describes why a solution of 6.00 g of Ca(NO3)2?in 30.0 g of water has a greater boiling-p

sukhopar [10]

Boiling-point elevation is a colligative property.

That means, the the boiling-point elevation depends on the molar content (fraction) of solute.

The dependency is ΔTb = Kb*m

Where ΔTb is the elevation in the boiling point, kb is the boiling constant, and m is the molality.

A solution of 6.00 g of Ca(NO3) in 30.0 g of water has 4 times the molal concentration of a solution of 3.00 g of Ca(NO3)2 in 60.0 g of water.:

(6.00g/molar mass) / 0.030kg = 200 /molar mass
(3.00g/molar mass) / 0.060kg = 50/molar mass

=> 200 / 50 = 4.

Then, given the direct proportion of the elevation of the boiling point with the molal concentration, the solution of 6.00 g of CaNO3 in 30 g of water will exhibit a greater boiling point elevation.

Or, what is the same, the solution with higher molality will have the higher boiling point.

5 0

3 years ago