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2 years ago

A spaceship is traveling through space. Suddenly, its speed increases. What can

Chemistry

1 answer:

asambeis [7]2 years ago

6 0

Answer:

A. The kinetic energy increases as its speed increases.

Explanation:

The kinetic energy of an object is energy possessed by an object by virtue of its motion.

Now, kinetic energy of a moving body is given by;

KE = 1/2 mv^2

Where;

m = mass of the body

v = velocity (speed) of the body

It follows that if the mass of the spaceship is constant, a sudden increase in speed leads to a corresponding increase in the kinetic energy of the spaceship in accordance with the relationship show above.

You might be interested in

Why are the alloys harder than pure iron

balu736 [363]

Answer:

Explanation:

Alloys are harder and stronger because the different-sized atoms of the mixed metals make the atomic layers less regular, so they cannot slide as easily.

6 0

2 years ago

Can anyone help with 5 through 8? Please :(

Aleksandr [31]

Answer:

The answer to your question is below

Explanation:

5) Fe₂O₃(s) + 3H₂O ⇒ 2Fe(OH)₃ (ac) Synthesis reaction

6) 2C₄H₁₀(g) + 13O₂(g) ⇒ 8CO₂ (g) + 10H₂O Combustion reaction

7) 2NO₂ (g) ⇒ 2O₂ (g) + N₂ (g) Decomposition reaction

8) H₃P (g) + 2O₂ (g) ⇒ PO (g) + 3H₂O Single replacement reaction

4 0

2 years ago

Rank the following atoms in order of decreasing first ionization energies (i.e., highest to lowest): Li, Be, Ba, F.

Minchanka [31]

Answer:

The order is:

F >Be >Li >Ba

Explanation:

Electrons are held in atoms by their attraction to the nucleus which means that to remove an electron from the atom energy is needed.

The ionization energy is the minimum energy necessary to remove an electron from an atom in the gas phase and ground state, the electron removed being the outermost, that is, the furthest from the nucleus. The further away the electron is from the nucleus, the easier it is to remove it, that is, the less energy is needed.

By increasing the atomic number of the elements of the same group, the nuclear attraction on the outermost electron decreases, since the atomic radius increases. Then the ionization energy decreases. In other words, in a group it decreases from top to bottom because the size of the atom increases and it is easier to remove an external electron.

By increasing the atomic number of the elements of the same period, the nuclear attraction on the outermost electron increases, since the atomic radius decreases. Therefore, in a period, as the atomic number increases, the ionization energy increases. In summary, in a period it increases from left to right as the effective nuclear charge increases and it increases thanks to the decrease in the size of the atom.

Taking these considerations into account, the order is:

5 0

2 years ago

A plot of 1/[BrO-] vs. time is linear and the slope is equal to 0.056 M-1s-1. If the initial concentration of BrO- is 0.65 M, ho

finlep [7]

Answer:

time taken for one-half of the BrO⁻ ion to react is t= 27.45 secs

Explanation:

equation of reaction

3BrO⁻(aq) → BrO₃⁻(aq) + 2Br⁻(aq) (second order reaction)

given

the slope of the graph is 0.056M⁻¹s⁻¹ = k(constant)

initial concentration [A]₀ = 0.65M

for second order reaction,we can calculate the time taken for one-half of the BrO- ion to react using:

$\frac{1}{[A]}$ = $\frac{1}{[A]}$ ₀ ⁺ k × t

where initial concentration [A]₀ = 0.65M

[A] = [A]₀÷2 = 0.325M

$\frac{1}{0.325M}$ = $\frac{1}{0.65M}$ + 0.056M⁻¹s⁻¹ × t

3.077= 1.54 + 0.056t

3.077-1.54=0.056t

1.537=0.056t

t= 27.45 secs

4 0

2 years ago

One mole of oxygen gas is at a pressure of 6.00 atm and a temperature of 27.0°C. (a) If the gas is heated at constant volume unt

Umnica [9.8K]

Answer: a) 900 K

b) 1200 K

Explanation:

According to the ideal gas equation:

$PV=nRT$

P = Pressure of the gas = 6.00 atm

V= Volume of the gas = ?

T= Temperature of the gas = 27°C = 300 K $0^00C=273K$

R= Gas constant = 0.0821 atmL/K mol

n= moles of gas = 1

$V=\frac{nRT}{P}=\frac{1\times 0.0821\times 300}{6.00}=4.10L$

a) To calculate the final temperature of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

$\frac{P_1}{T_1}=\frac{P_2}{T_2}$