Answer:
21g
Explanation:
no.ofmol fe2o3=39.5/(56×2+16×3)=0.25mol
from equation 1mole fe2o3 react with 3mole co
so,0.25mol fe2o3 react with 0.75mol co
mass of co=0.75×(12+16)=21g
Answer:
V₂ = 106.5 mL
Explanation:
Given data:
Initial volume =200 mL
Initial pressure = 2 atm
Initial temperature = 35 °C (35 +273 = 308 K)
Final temperature = 55°C (55+273 = 328 K)
Final volume = ?
Final pressure = 4 atm
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 2 atm ×200 mL × 328 K / 308 K ×4 atm
V₂ = 131200 atm .mL. K / 1232 K.atm
V₂ = 106.5 mL
1. Curiosity
2.<span> Necessity</span>
Answer:
The rows running from left to right are called Periods and the columns going up and down are called Groups.
Explanation:
The answer is Abecaue it is the most specific on how
