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2 years ago

Why the dipole moment of Co2 is zero and that of H2O is 1.85D?

Chemistry

1 answer:

valentina_108 [34]2 years ago

6 0

Answer/ explanation :

In CO2 molecule, the angle between O-C-O is 180, therefore, when the oxygen atom attracts the electron pair towards itself, then it becomes partially negative and the carbon atom becomes partially positive. The bonds in O=C=O are pointing opposite each other and the bond dipoles cancels each other thereby making it zero.

The dipole in O-H bonds cannot cancel out and that is why water has an overall molecular dipole of 1.85D.

CO2 is a linear molecule, so the dipoles are symmetrical. The dipoles are equal in both magnitude but are differ in point facing opposite directions.

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A method used by the U.S. Environmental Protection Agency (EPA) for determining the concentration of ozone in air is to pass the

baherus [9]

Answer: 1. $9.08\times 10^{-6}$ moles

2. 90 mg

Explanation:

$O_3(g)+2NaI(aq)+H_2O(l) \rightarrow O_2(g)+I_2(s)+2NaOH(aq)$

According to stoichiometry:

1 mole of ozone is removed by 2 moles of sodium iodide.

Thus $4.54 \times 10^{-6}$ moles of ozone is removed by = $\frac{2}{1}\times 4.54 \times 10^{-6}=9.08\times 10^{-6}$ moles of sodium iodide.

Thus $9.08\times 10^{-6}$ moles of sodium iodide are needed to remove $4.54\times 10^{-6}$ moles of $O_3$

2. $\text{Number of moles of ozone}=\frac{0.01331g}{48g/mol}=0.0003moles$

According to stoichiometry:

1 mole of ozone is removed by 2 moles of sodium iodide.

Thus 0.0003 moles of ozone is removed by = $\frac{2}{1}\times 0.0003=0.0006$ moles of sodium iodide.

Mass of sodium iodide= $moles\times {\text {molar mass}}=0.0006\times 150g/mol=0.09g=90mg$ (1g=1000mg)

Thus 90 mg of sodium iodide are needed to remove 13.31 mg of $O_3$ .

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2 years ago

Which of the following is an electrolyte? a. PbCl2 b. MgS c. HNO3 d. Al2(Cr2O7)3

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Answer: A: PbCl2

Hope dis helps!

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2 years ago

Material A has a small latent heat of fusion. Material B has a large heat of fusion. Which of the following statements is true?

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2 years ago

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How many liters of 4.0 M NaOH solution will react with 0.60 liters 3.0 M H2SO4?

slava [35]

Answer:

A. 0.90 L.

Explanation:

NaOH solution will react with H₂SO₄ according to the balanced reaction:

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O.

1.0 mole of H₂SO₄ reacts with 2.0 moles of NaOH.

For NaOH to react completely with H₂SO₄, the no. of millimoles should be equal.

∴ (MV) NaOH = (xMV) H₂SO₄.

x for H₂SO₄ = 2, due to having to reproducible H⁺ ions.

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2 years ago

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olga2289 [7]

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