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3 years ago

Why the dipole moment of Co2 is zero and that of H2O is 1.85D?

Chemistry

1 answer:

valentina_108 [34]3 years ago

6 0

Answer/ explanation :

In CO2 molecule, the angle between O-C-O is 180, therefore, when the oxygen atom attracts the electron pair towards itself, then it becomes partially negative and the carbon atom becomes partially positive. The bonds in O=C=O are pointing opposite each other and the bond dipoles cancels each other thereby making it zero.

The dipole in O-H bonds cannot cancel out and that is why water has an overall molecular dipole of 1.85D.

CO2 is a linear molecule, so the dipoles are symmetrical. The dipoles are equal in both magnitude but are differ in point facing opposite directions.

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How many atoms of oxygen are contained in 160 grams if N2O3?

Juli2301 [7.4K]

Answer:

3.80x1024 grams containing if not that then above 80 grams 6 grams

Explanation:

3 0

3 years ago

Read 2 more answers

Problem Page Question It takes to break a carbon-carbon single bond. Calculate the maximum wavelength of light for which a carbo

Marizza181 [45]

This is a incomplete question. The complete question is:

It takes 348 kJ/mol to break a carbon-carbon single bond. Calculate the maximum wavelength of light for which a carbon-carbon single bond could be broken by absorbing a single photon. Round your answer to correct number of significant digits

Answer: 344 nm

Explanation:

$E=\frac{Nhc}{\lambda}$

E= energy = 348kJ= 348000 J (1kJ=1000J)

N = avogadro's number = $6.023\times 10^{23}$

h = Planck's constant = $6.626\times 10^{-34}Js
$

c = speed of light = $3\times 10^8ms^{-1}$

$348000=\frac{6.023\times 10^{23}\times 6.626\times 10^{-34}\times 3\times 10^8}{\lambda}$

$\lambda=\frac{6.023\times 10^{23}\times 6.626\times 10^{-34}\times 3\times 10^8}{348000}$

$\lambda=3.44\times 10^{-7}m=344nm$ $1nm=10^{-9}m$

Thus the maximum wavelength of light for which a carbon-carbon single bond could be broken by absorbing a single photon is 344 nm

5 0

3 years ago

A sample of a pure compound that weighs 59.8 g contains 27.6 g Sb (antimony) and 32.2 g F (fluorine). What is the percent compos

Rama09 [41]

Answer:

53.85%

Explanation:

Data obtained from the question include:

Mass of antimony (Sb) = 27.6g

Mass of Fluorine (F) = 32.2g

Mass of compound = 59.8g

Percentage composition of fluorine (F) =..?

The percentage composition of fluorine can be obtained as follow:

Percentage composition of fluorine = mass of fluorine/mass of compound x 100

Percentage composition of fluorine = 32.2/59.8 x 100

= 53.85%

Therefore, the percentage composition of fluorine in the compound is 53.85%

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3 years ago

How are models useful in describing how molecules are formed

Nady [450]

Answer:

The purpose of molecular modeling is to provide a three-dimensional image (either physical or software-based) that allows a chemist to better see the manner in which atoms and molecules can interact. These models can be used to interpret existing observations or to predict new chemical behavior.

Explanation:

It can describe shape and how they connect while forming the electrons.

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3 years ago

Based on your knowledge of intermolecular forces and trends, select the statement that is most accurately compares HF and HCl.

tangare [24]

Answer:

(A) The intermolecular attraction between HF molecules are stronger than between HCl molecules mainly to due hydrogen bonding.

Explanation:

Since Flourine is highly electronegative and as such, when it bonds with Hydrogen it forms a hydrogen bond. Whereas the HCL molecule is a polar molecule whose inter-molecular forces are dipole dipole interactions. Although a Hydrogen bond is a type of dipole dipole interaction it is stronger than the traditional dipole dipole forces and London dispersion forces. HF also has a shorter bond length which makes the bond and inter-molecular forces stronger as compared to HCL.

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3 years ago