$\bf (7x-6)\times (3x^2-4x+5)\implies \begin{array}{cllll} 3x^2-4x+5\\ \times 7x\\\cline{1-1} 21x^3-28x^2+35x \end{array}~~ +~~ \begin{array}{cllll} 3x^2-4x+5\\ \times -6\\\cline{1-1} -18x^2+24x-30 \end{array} \\\\\\ 21x^3-28x^2+35x~~+~~(-18x^2+24x-30)\implies \boxed{21x^3-46x^2+59x-30}$

3 0

2 years ago

The sum of the lengths of any two sides of a triangle must be greater than the third side. If a triangle has one side that is 8

julsineya [31]

Good afternoon,

First side= 8cm
Third side= x
Second side= 2x-4

We know that the sume of the lenghts of any two sides must be greater than the third side, so:

$Second \,\,\,\,side+Third\,\,\,\,side>First\,\,\,\,side \\ 2x-4 + x >8 \\ 3x>12 \\ x>4
$

Answer: Third side= x ; where: x>4 or (4,+infinity)
Second side= 2x-4 ; where: x>4 or (4,+infinity)

3 0

2 years ago

What's 0.4 in a fraction in the simplest form?

bezimeni [28]

$0.4=\frac{4}{10}=\frac{4:2}{10:2}=\boxed{\frac{2}{5}}$

5 0

2 years ago

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