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GrogVix [38]
1 year ago
6

a bag contains 2 coins, one fair and the other with 2 heads. you pick 1 coin at random and flip it. what is the probability that

you picked the fair coin given that the outcome of the toss was heads?
Mathematics
1 answer:
Nezavi [6.7K]1 year ago
4 0

The probability that you picked the fair coin given that the outcome of the toss was heads is 1/3.

There is a one in two chance of drawing the fair coin. The chances of flipping heads again are 1 in 2. As a result, there is a 1 in 4 chance that the coin will land on heads.

There is a one in two chance of drawing the trick coin. The probability of flipping heads is then 2 to 1. As a result, there is a 2 in 4 chance that the coin will land on heads.

When each is multiplied by four, the resulting integers are

fair: 1 and trick: 2

and overall results: 3. (fair and tails is not counted)

The likelihood of a fair coin is one in three.

The likelihood that the chosen coin will show heads and be the fair coin is 33.333%.

To learn more about probability

brainly.com/question/14531945

#SPJ4

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We get;

12 = \dfrac{30}{1 + 5\cdot e^{-(30\cdot k) \cdot 20}}

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H = \dfrac{30}{1 + 5\cdot e^{-(30\times 6.7577518 \times 10^{-4}) \cdot t}} =  \dfrac{30}{1 + 5\cdot e^{-(2.02732554 \times 10^{-3}) \cdot t}}

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At t = 30, we have;

H =  \dfrac{30}{1 + 5\cdot e^{-(2.02732554 \times 10^{-3}) \times 30}} \approx 19.4258866473

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