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Anna71 [15]
1 year ago
15

How many protons, neutrons, and electrons for b+5

Chemistry
1 answer:
Aliun [14]1 year ago
8 0

Explanation:

It has 5 protons,6 neutrons, 5 electrons.

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What is the name of this compound? H single bonded to N with a pair of electron dots above and a single bond to H below, single
dybincka [34]

Answer:

Ethanamine (also known as ethylamine)

Explanation:

The compound that is requested by the question is ethanamine. Its trivial name is ethylamine.

It is a compound that contained the ethyl moiety (CH3CH2-) as well as the amine moiety (-NH2).

Ethanamine has a structure that can easily be determined by the statements in the question.

The structure of ethanamine is shown in the image attached.

4 0
3 years ago
Select all the statements that correctly describe a solution. Multiple select question.
motikmotik

Answer:

B, D, C

Explanation:

the solution may have more than one solute, a solution is a homogenous mixture of 2 or more substances and not all solutions are liquid

8 0
2 years ago
Which compound is classified as a hydrocarbon? A) butanal B) butyne C) 2-butanol D) 2-butanone
fenix001 [56]

Answer:

butyne

Explanation:

alkane, alkene, and alkyne are all examples of hydrocarbons.

butyne = alkyne

7 0
3 years ago
When sodium is excited in a flame, two ultraviolet spectral lines at (wave length symbol)=372.1 nm and (wave length symbol)=376.
uranmaximum [27]
<span>Higher energy = shorter wavelength
Frequency is one cycle over an amount of time (seconds)
So higher frequency = higher energy = shorter wavelength</span>
5 0
4 years ago
Read 2 more answers
A 35.40 gram hydrate of sodium carbonate, Na2CO3•nH2O, is heated to a constant mass. Its final weight is 30.2 g. What is formula
Sever21 [200]

Answer:

Na₂CO₃•H₂O

Explanation:

After it is heated, the remaining mass is the mass of sodium carbonate.

30.2 g Na₂CO₃

Mass is conserved, so the difference is the mass of the water:

35.4 g − 30.2 g = 5.2 g H₂O

Convert masses to moles:

30.2 g Na₂CO₃ × (1 mol Na₂CO₃ / 106 g Na₂CO₃) = 0.285 mol Na₂CO₃

5.2 g H₂O × (1 mol H₂O / 18.0 g H₂O) = 0.289 mol H₂O

Normalize by dividing by the smallest:

0.285 / 0.285 = 1.00 mol Na₂CO₃

0.289 / 0.285 = 1.01 mol H₂O

The ratio is approximately 1:1.  So the formula of the hydrate is Na₂CO₃•H₂O.

3 0
3 years ago
Read 2 more answers
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