Answer:
The answer to your question is 0.04 M
Explanation:
Data
mass of Na₂SO₄ = 14.2 g
volume = 2.50 l
Molarity = ?
Process
1.- Calculate the molar mass of Na₂SO₄
Na₂SO₄ = (23 x 2) + (32 x 1) + (16 x 4) = 46 + 32 + 64 = 142 g
2.- Calculate the number of moles of Na₂SO₄
142 g of Na₂SO₄ ------------------- 1 mol
14.2 g of Na₂SO₄ ------------------ x
x = (14.2 x 1) / 142
x = 0.1 moles
3.- Calculate the molarity
Molarity = moles /volume
-Substitution
Molarity = 0.1 / 2.5
-Result
Molarity = 0.04
Answer:
B - Eukaryotic
Explanation:
Fungi are eukaryotic organisms that appeared on land more than 450 million years ago. They are heterotrophs and contain neither photosynthetic pigments such as chlorophyll nor organelles such as chloroplasts. Because fungi feed on decaying and dead matter, they are saprobes.
Answer : The molal freezing point depression constant of liquid X is, 
Explanation : Given,
Mass of urea (solute) = 5.90 g
Mass of liquid X (solvent) = 450 g = 0.450 kg
Molar mass of urea = 60 g/mole
Formula used :
where,
= change in freezing point
= freezing point of solution = 
= freezing point of liquid X = 
i = Van't Hoff factor = 1 (for non-electrolyte)
= Molal-freezing-point-depression constant = ?
m = molality
Now put all the given values in this formula, we get
Therefore, the molal freezing point depression constant of liquid X is,
