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2 years ago

Which of the newman structures below represents this conformation of 2-methyl-3-pentanol, as viewed along the c2-c3 bond?

Chemistry

1 answer:

castortr0y [4]2 years ago

5 0

Answer:

(4) option is correct

Explanation:

Given that,

The conformation of 2-methyl-3-pentanol, as viewed along the C₂-C₃ bond.

We need to find the Newman structures

Using given structures

The structure of 2- methyl-3- pentanol is shown in figure.

Through C₂-C₃ carbon shown the structure of Newman projection in figure.

Here, carbon 2 is in front side and carbon 3 is in back side in the figure.

Hence, (4) option is correct.

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The __________________ of a solution tells how many moles of solute are present per liter.

Stels [109]

Answer:

The MOLARITY of a solution tells how many moles of solute are present per liter

Explanation:

Molarity is a sort of concentration.

It is written as M (mol/L)

5 0

2 years ago

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Where is ocean water the densest?

Vika [28.1K]

Answer:

your answer should be the bottom

sorry if im wrong

Explanation:

8 0

2 years ago

I NEED HELP PLEASE, THANKS! :)

krok68 [10]

Answer:

$\large \boxed{\text{2.20 g Pb}}$

Explanation:

They gave us the masses of two reactants and asked us to determine the mass of the product.

This looks like a limiting reactant problem.

1. Assemble the information

We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.

Mᵣ: 239.27 32.00 207.2

2PbS + 3O₂ ⟶ 2Pb + 2SO₃

m/g: 2.54 1.88

2. Calculate the moles of each reactant

$\text{Moles of PbS} = \text{2.54 g PbS } \times \dfrac{\text{1 mol PbS}}{\text{239.27 g PbS}} = \text{0.010 62 mol PbS}\\\\\text{Moles of O}_{2} = \text{1.88 g O}_{2} \times \dfrac{\text{1 mol O}_{2}}{\text{32.00 g O}_{2}} = \text{0.058 75 mol O}_{2}$

3. Calculate the moles of Pb from each reactant

$\textbf{From PbS:}\\\text{Moles of Pb} = \text{0.010 62 mol PbS} \times \dfrac{\text{2 mol Pb}}{\text{2 mol PbS}} = \text{0.010 62 mol Pb}\\\\\textbf{From O}_{2}:\\\text{Moles of Pb} =\text{0.058 75 mol O}_{2} \times \dfrac{\text{2 mol Pb}}{\text{3 mol O}_{2}}= \text{0.039 17 mol Pb}\\\\\text{PbS is the $\textbf{limiting reactant}$ because it gives fewer moles of Pb}$

4. Calculate the mass of Pb

$\text{ Mass of Pb} = \text{0.010 62 mol Pb} \times \dfrac{\text{207.2 g Pb}}{\text{1 mol Pb}} = \textbf{2.20 g Pb}\\\\\text{The reaction produces $\large \boxed{\textbf{2.20 g Pb}}$}$

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2 years ago

Hydrogen iodide can decompose into hydrogen and iodine gases. 2 HI(g) H2(g) + 12(g) Kp for the reaction is 0.016. If 0.350 atm o

solniwko [45]

Answer : The total pressure at equilibrium is 0.350 atm

Solution : Given,

Initial pressure of $HI$ = 0.350 bar

$K_p$ = 0.016

The given equilibrium reaction is,

$2HI(g)\rightleftharpoons H_2(g)+I_2(g)$

Initially 0.350 0 0

At equilibrium (0.350-2x) x x

The total pressure at equilibrium = $(0.350-2x)+x+x=0.350-2x+2x=0.350atm$

Thus, the total pressure at equilibrium is 0.350 atm

4 0

2 years ago

Over a period of 30 days a student studied the night sky and recorded his observations. One night he watched a shooting star str

Temka [501]

Answer:

meteor

Explanation:

The most logical identification of a "shooting star" is a meteor. A meteor is basically any material from outerspace that falls to Earth. The main characteristic of a meteor is that from our point of view on the surface of the Earth it looks like a shooting star because we see a streak of light behind it. This light is simply dust and rock from the meteor burning up as it enters the Earth's atmosphere, leaving a "tail" of light behind it. Which to us looks like a shooting star.

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2 years ago