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GalinKa [24]
4 years ago
9

When water exposed to the air changes from liquid to gas

Chemistry
2 answers:
Neko [114]4 years ago
3 0
What Can you be more clear --Molecules change it from being less dense
Bad White [126]4 years ago
3 0
Yes it does because when the water is heated up or something is changes from a liquid to a gas.
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Calculate the freezing point of a 12.25 m 12.25m aqueous solution of propanol. Freezing point constants can be found in the list
vichka [17]

Answer:

∆t(f) = 49.755C

Explanation:

Freezing point is defined as the point in which a liquid changes from liquid to solid state. Therefore, to calculate the freezing point of aqueous solution of propanol

∆t = k × I × m

Where k is cryscopic constant =

I = vant Hoff factor = 2

M = molar concentration = 12.25m

∆t (f) = 1.9 × 12.25 × 2 = 49.755C

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3 years ago
Which of the folowing is true about radio waves?
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3 years ago
Identify each definition that applies to the compound in red. Check all that apply. Upper F superscript minus in red plus upper
likoan [24]

The fluoride ion in the reaction has been the acceptor of the hydrogen. Thus, the fluoride ion has been the Brønsted Lowry base.

<h3 /><h3>What is the Brønsted Lowry acid and base concept?</h3>

The Brønsted Lowry acid and base concept can be described based on the proton acceptor and donor. The Brønsted Lowry acid has been the proton donor, and the Brønsted Lowry base has been the proton acceptor.

The Arrhenius concept is based on hydrogen and hydroxide donors. The Arrhenius base has been the hydroxide donor, and the Arrhenius acid has been the hydrogen donor.

Since the fluoride ion has been the proton acceptor in the reaction, it has been the Brønsted Lowry base.

Lear more about Brønsted Lowry acid and base, here:

brainly.com/question/21736327

4 0
2 years ago
Determine the enthalpy change for the reaction 2C(s) + 2H2O(g) → CH4(g) + CO2(g) using the following:
Sophie [7]

Answer : The enthalpy change for the reaction is, 97.7 kJ

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The given main chemical reaction is,

2C(s)+3H_2O(g)\rightarrow CH_4(g)+CO_2(g)    \Delta H=?

The intermediate balanced chemical reaction will be,

(1) C(s)+H_2O(g)\rightarrow CO(g)+H_2(g)     \Delta H_1=131.3kJ

(2) CO(g)+H_2O(g)\rightarrow CO_2(g)+H_2(g)    \Delta H_2=41.2kJ

(3) CH_4(g)+H_2O(g)\rightarrow 2H_2(g)+CO(g)    \Delta H_3=206.1kJ

Now we are multiplying reaction 1 by 2 and reversing reaction 3 and then adding all the equations, we get :

(1) 2C(s)+2H_2O(g)\rightarrow 2CO(g)+2H_2(g)     \Delta H_1=2\times 131.3kJ=262.6kJ

(2) CO(g)+H_2O(g)\rightarrow CO_2(g)+H_2(g)    \Delta H_2=41.2kJ

(3) 2H_2(g)+CO(g)\rightarrow CH_4(g)+H_2O(g)    \Delta H_3=-206.1kJ

The expression for enthalpy of main reaction will be,

\Delta H=\Delta H_1+\Delta H_2+\Delta H_3

\Delta H=(262.6)+(41.2)+(-206.1)

\Delta H=97.7kJ

Therefore, the enthalpy change for the reaction is, 97.7 kJ

3 0
4 years ago
Read 2 more answers
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