<span>Pressure = force / area</span>
I assume that 350kg is the mass
Therefore,
350 x 9.8 (gravity) = 3430N
3430 / 1 = 3430Pa
3.43 KPa
Answer:
No, it is not conserved
Explanation:
Let's calculate the total kinetic energy before the collision and compare it with the total kinetic energy after the collision.
The total kinetic energy before the collision is:
![K_i = K_1 + K_2 = \frac{1}{2}mv_1^2 + \frac{1}{2}mv_2^2=\frac{1}{2}(1 kg)(2 m/s)^2+\frac{1}{2}(1 kg)(0)^2=2 J](https://tex.z-dn.net/?f=K_i%20%3D%20K_1%20%2B%20K_2%20%3D%20%5Cfrac%7B1%7D%7B2%7Dmv_1%5E2%20%2B%20%5Cfrac%7B1%7D%7B2%7Dmv_2%5E2%3D%5Cfrac%7B1%7D%7B2%7D%281%20kg%29%282%20m%2Fs%29%5E2%2B%5Cfrac%7B1%7D%7B2%7D%281%20kg%29%280%29%5E2%3D2%20J)
where m1 = m2 = 1 kg are the masses of the two carts, v1=2 m/s is the speed of the first cart, and where v2=0 is the speed of the second cart, which is zero because it is stationary.
After the collision, the two carts stick together with same speed v=1 m/s; their total kinetic energy is
![K_f = \frac{1}{2}(m_1+m_2)v^2=\frac{1}{2}(1 kg+1kg)(1 m/s)^2=1 J](https://tex.z-dn.net/?f=K_f%20%3D%20%5Cfrac%7B1%7D%7B2%7D%28m_1%2Bm_2%29v%5E2%3D%5Cfrac%7B1%7D%7B2%7D%281%20kg%2B1kg%29%281%20m%2Fs%29%5E2%3D1%20J)
So, we see that the kinetic energy was not conserved, because the initial kinetic energy was 2 J while the final kinetic energy is 1 J. This means that this is an inelastic collision, in which only the total momentum is conserved. This loss of kinetic energy does not violate the law of conservation of energy: in fact, the energy lost has simply been converted into another form of energy, such as heat, during the collision.
Answer:
D
Explanation:
they can see this along with many other fish.
If you put a penny in each light spot the penny that the light is shining on will recive the most energy.