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dybincka [34]
4 years ago
11

-SCIENCE-

Physics
2 answers:
zlopas [31]4 years ago
7 0
Bronchial Tubes
hope this helps :)
Alisiya [41]4 years ago
7 0
The bronchi. (singular - Bronchus)
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Which of the following requires constant agonist-antagonist muscle contraction
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Answer: Dynamic balance

Explanation: Dynamic balance movements are movements in which constant agonist-antagonist muscle contractions occur in order to maintain a certain position or posture. ISSA pg 121

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3 years ago
If you want to calculate the acceleration of a car, you should _____ the change in velocity of the car by the time interval.
Neporo4naja [7]

Answer:

Your awnser is B. Increase

Explanation:

5 0
3 years ago
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If red light hits a red filter, what kind of light comes through the filter?
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A. red, is the correct answer. A red filter only lets red light through, whether white or red light passes through it.
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8 0
4 years ago
A centrifugal pump rotates at n˙ = 740 rpm. Suppose the pump has some swirl at the inlet (α1 = 10°) and exits at an angle of 35°
Blizzard [7]

Answer:

Net head = 380cm

bhp = 17.710kW

Explanation:

Angular velocity of centrifugal pump:

w=\frac{2\pi n}{60}=\frac{2\pi (750)}{60}=78.54\frac{rad}{s}

Normal velocity component at outlet of pump:

V_{2,n}=\frac{V}{2\pi r_{2}b_{2}}=\frac{0.573}{2\pi (0.24)(0.162)}}=2.346\frac{m}{s}

Tangential velocity component at exit of the pump:

V_{2,t}=v_{2,n}tan\alpha _{2}=(2.346)tan(35)=1.643\frac{m}{s}

Normal velocity component at inlet of pump:

V_{1,n}=\frac{V}{2\pi r_{1} b_{1}}=\frac{0.573}{2\pi (0.12)(0.18)}=4.22\frac{m}{s}

Tangential velocity component at inlet of the pump:

V_{1,t}=v_{1,n}tan\alpha _{1}=(4.22)tan(0)=0\frac{m}{s}

Equivalent head in centimetre of water column:

H_{water}=H(\frac{rho_{air}}{rho_{water}})\\\\H_{water}=(\frac{w}{g} )(r_{2}V_{2,t}-r_{1}V_{1,t})(\frac{rho_{air}}{rho_{water}}) \\\\H_{water}=(\frac{78.54}{9.81})((0.24)(1.643)-(0.12)(0)})(\frac{1.2}{998})=38m=380cm

Break horse power:

bhp=rho_{water} gHV=rho_{water} g[(\frac{w}{g})(r_{2}V_{2,t}-r_{1}V_{1,t})]V\\\\bhp=(998)(9.81)[(\frac{78.54}{9.81})((0.24)(1.643)-(0.12)(0))](0.573)=17710W=17.710kW

8 0
3 years ago
The field inside a charged parallel-plate capacitor is __________.
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<span>Uniform. A parallel plate capacitor is a simple arrangement of electrodes and dielectric to form a capacitor. Here two parallel conductive plates are used as electrodes with a medium or dielectric in between them. Charge separation in a parallel-plate capacitor causes an internal electric field, which is uniform.</span>
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4 years ago
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