Answer:
At the distance of 0.220cm from the axis.
r = 0.220cm = 0.0022m, E = 490N/C, e0 = 8.854 x 10^-12F/m
Linear charge density = 2*π*e0*r*E = 2 x 3.142 x 8.854x10^-12 x 0.0022 x 490 = 5.998 x 10^-11C/m
Thus, To Calculate the Electric field at the distance r = 0.616cm from the cylinder axis, we substitute the calculated linear change density in the equation
E = (linear charge density)/2*π*e0*r
Here, r = 0.616cm = 0.00616m
E = [(5.998 x 10^-11)/(2 x 3.142 x 8.854 x 10-12 x 0.00616)]
E = 175N/C
Explanation:
The Electric field of a charged conducting cylinder obey the Gauss Law.
Therefore, the Electric field is given as:
E = (linear charge density)/4πe0r,
Where e0 is the permittivity of free space with constant value of 8.854 x 10^-12F/m, r is the radial distance from the axis.
