1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
anzhelika [568]
3 years ago
15

If the current in this circuit is 3 A, what must be the value of R3?

Physics
1 answer:
Ronch [10]3 years ago
7 0

Answer:

5

Explanation:

You might be interested in
Physics pls help
seropon [69]
First one is correct
3 0
3 years ago
Read 2 more answers
What to press when leaving laptop for a moment?
olga nikolaevna [1]
Pressing (Win+L) will quickly lock a laptop

8 0
3 years ago
Write and solve a MA or efficiency problem
GuDViN [60]
Input energy is: 200 joule
Output energy is: 100 joule

100/200*100=%50 efficiency
8 0
3 years ago
The parallel axis theorem relates Icm, the moment of inertia of an object about an axis passing through its center of mass, to I
erma4kov [3.2K]

Answer:

Part a)

I_{end} = \frac{mL^2}{3}

Part b)

I_{edge} = \frac{2ma^2}{3}

Explanation:

As we know that by parallel axis theorem we will have

I_p = I_{cm} + Md^2

Part a)

here we know that for a stick the moment of inertia for an axis passing through its COM is given as

I = \frac{mL^2}{12}

now if we need to find the inertia from its end then we will have

I_{end} = I_{cm} + Md^2

I_{end} = \frac{mL^2}{12} + m(\frac{L}{2})^2

I_{end} = \frac{mL^2}{3}

Part b)

here we know that for a cube the moment of inertia for an axis passing through its COM is given as

I = \frac{ma^2}{6}

now if we need to find the inertia about an axis passing through its edge

I_{edge} = I_{cm} + Md^2

I_{edge} = \frac{ma^2}{6} + m(\frac{a}{\sqrt2})^2

I_{edge} = \frac{2ma^2}{3}

7 0
3 years ago
Newly discovered planet has twice the mass and three times the radius of the earth. What is the free-fall acceleration at its su
skad [1K]

Answer:

g_n=\dfrac{2}{9}g

Explanation:

M = Mass of Earth

G = Gravitational constant

R = Radius of Earth

The acceleration due to gravity on Earth is

g=\dfrac{GM}{R^2}

On new planet

g_n=\dfrac{G2M}{(3R)^2}\\\Rightarrow g_n=\dfrac{2GM}{9R^2}

Dividing the two equations we get

\dfrac{g_n}{g}=\dfrac{\dfrac{2GM}{9R^2}}{\dfrac{GM}{R^2}}\\\Rightarrow \dfrac{g_n}{g}=\dfrac{2}{9}\\\Rightarrow g_n=\dfrac{2}{9}g

The acceleration due to gravity on the other planet is g_n=\dfrac{2}{9}g

4 0
3 years ago
Read 2 more answers
Other questions:
  • Tidal forces are gravitational forces exerted on different parts of a body by a second body. Their effects are particularly visi
    5·1 answer
  • A 0.80 kg mass attached to an ideal spring oscillates horizontally with a period of 0.50 s and amplitude of 0.30 m. What is the
    10·1 answer
  • Which is true of a step-down transformer but not a step-up transformer? The core is made of copper and the coils are made of iro
    11·2 answers
  • laser light hits two very narrow slits that are separated by 0.1mm adn is viewwed on a screen 2m downstream. Sketch on the axis
    5·2 answers
  • Water is entering the prism at a rate of A m^3/hr. The prism is empty at time 0. Express the depth d of the water in meters in t
    9·1 answer
  • I need help on this and the first person who will answer this correctly gets BRANLIST​
    14·1 answer
  • During radioactive decay, ___ energy was transformed to ____
    11·1 answer
  • A car moves to the right as shown. In order for the car to slow down, the acceleration must
    13·2 answers
  • The graph shows the layers of Earth's atmosphere. Which statement best describes the relationship between temperature and altitu
    13·1 answer
  • the mass of an object is 90 kg calculate weight of the same object on the surface of the moon.(acceleration due to gravity on th
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!