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mrs_skeptik [129]
4 years ago
10

Write the word sentence as an equation.

Mathematics
2 answers:
Katyanochek1 [597]4 years ago
7 0
The answer you are looking for is -5

rosijanka [135]4 years ago
4 0
Sum means that two values are being added together. In this case, the two values are y and -3. The problem tells us that the sum of these two values equals -8.

So, the equation is y + (-3) = -8

Hope that makes sense!
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Positive or negative depositing $85 in a bank account.Is that a positive or negative
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Negative because you take the money out
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4 years ago
What is the simplest form of 324xy³2<br> ?
cestrela7 [59]

Answer:

2² * 3⁴ * x * y³

Step-by-step explanation:

<h3>Simplify:</h3>

   First prime factorize 324

 324 = 2 * 2 * 3 * 3 * 3 * 3

Now , write in exponent form:

324 = 2²*3⁴

324xy³ =2² * 3⁴ * x * y³

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2 years ago
What if the perimeter of the table?
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Step-by-step explanation:

13? i forgot all this math XD

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3 years ago
Read 2 more answers
Graph -x^2+x+6=0 and state the consecutive integers between which roots are located
KengaRu [80]

Answer:

The roots of given quadratic equation lies from \begin{bmatrix}-2 , 3 \end{bmatrix}

Step-by-step explanation:

Given as :

The quadratic equation is x² - x -6 = 0

The quadratic equation is in form of ax² + bx +c = 0

Let x1 and x2 be the roots of equation

Sum of roots

So, x1 + x2 = \frac{-b}{a}  

And products of roots is x1 × x2 = \frac{c}{a}

So, x1 + x2 = \frac{1}{1}  

Or,   x1 + x2 = 1          ......A

And  x1 × x2 = \frac{-6}{1}

Or,  x1 × x2 = - 6

Now, (x1 - x2)² = (x1 + x2)²+ 4×x1×x2

Or,  (x1 - x2)² = (1)²+ 4×6

Or,  (x1 - x2)² = 25

So , x1 - x2 = \sqrt{25} = 5          ......B

Now solve eq A and eq B

Or, (x1 + x2) + (x1 - x2) = 1 +5

Or, 2 x1 = 6

∴   x1 = 3     And     x2 = - 2

Hence The roots of given quadratic equation lies from \begin{bmatrix}-2 , 3 \end{bmatrix}   Answer

6 0
4 years ago
Convert the polar representation of this complex number into its standard form:
7nadin3 [17]

Answer:

Step-by-step explanation:

z = 2(cos7π/6 +isin7π/6)

cos7π/6 = cos(π/6+π) = - cos(π/6) = - √3 /2

sin7π/6 = sin(π/6+π) = - sin(π/6) = - 1 /2

so : z = 2( - √3 /2+i(- 1 /2))

z=  - √3 - i .....(standard form)

4 0
4 years ago
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