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1 year ago

15

Which one doesn't belong explain why you chose that answer.

1 answer:

Liono4ka [1.6K]1 year ago

3 0

Answer:

2 because the unit rate is not the same for all the others it is consistant

Step-by-step explanation:

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How many 1/16 inches are in one inch?

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The answer is 16 inches are in 1/16 inches

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3 years ago

in a game, what card would you need to draw to get a score of 0 if you have a (-16), (-35), and 18 in your hand?

m_a_m_a [10]

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why the negitives

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in in secod grad

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3 years ago

going into the final exam which will count as two tests amelia has test scores of 79, 86, 74, 63, and 94. What score does amelia

stealth61 [152]

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going into the final exam which will count as two tests amelia has test scores of 79, 86, 74, 63, and 94. What score does amelia need on the final in order to have an average score of 80

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1 year ago

What are Factors of 98

Likurg_2 [28]

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4 years ago

Solve the following equation by factoring:9x^2-3x-2=0

olya-2409 [2.1K]

Answer:

The two roots of the quadratic equation are

$x_1= - \frac{1}{3} \text{ and } x_2= \frac{2}{3}$

Step-by-step explanation:

Original quadratic equation is $9x^{2}-3x-2=0$

Divide both sides by 9:

$x^{2} - \frac{x}{3} - \frac{2}{9}=0$

Add $\frac{2}{9}$ to both sides to get rid of the constant on the LHS

$x^{2} - \frac{x}{3} - \frac{2}{9}+\frac{2}{9}=\frac{2}{9}$ ==> $x^{2} - \frac{x}{3}=\frac{2}{9}$

Add $\frac{1}{36}$ to both sides

$x^{2} - \frac{x}{3}+\frac{1}{36}=\frac{2}{9} +\frac{1}{36}$

This simplifies to

$x^{2} - \frac{x}{3}+\frac{1}{36}=\frac{1}{4}$

Noting that (a + b)² = a² + 2ab + b²

If we set a = x and b = $\frac{1}{6}\right)$ we can see that

$\left(x - \frac{1}{6}\right)^2$ = $x^2 - 2.x. (-\frac{1}{6}) + \frac{1}{36} = x^{2} - \frac{x}{3}+\frac{1}{36}$

So

$\left(x - \frac{1}{6}\right)^2=\frac{1}{4}$

Taking square roots on both sides

$\left(x - \frac{1}{6}\right)^2= \pm\frac{1}{4}$

So the two roots or solutions of the equation are

$x - \frac{1}{6}=-\sqrt{\frac{1}{4}}$ and $x - \frac{1}{6}=\sqrt{\frac{1}{4}}$

$\sqrt{\frac{1}{4}} = \frac{1}{2}$

So the two roots are

$x_1=\frac{1}{6} - \frac{1}{2} = -\frac{1}{3}$

and

$x_2=\frac{1}{6} + \frac{1}{2} = \frac{2}{3}$

7 0

2 years ago