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yan [13]
1 year ago
12

If a wave of red light has a wavelength of 6.7 x 10-7 m, what is the frequency of the red wave?

Chemistry
1 answer:
morpeh [17]1 year ago
5 0

The frequency of the red wave, f = 2.78 x10¹¹ Hz.

<h3>Equation :</h3>

To find the wavelength,

f = v / λ

where,

f is frequency

v is speed wave of light

λ is wavelength of light

Known data,

wavelength of light, λ = 6.7 x 10⁻⁷

speed of red light, v = 1.86 x 10⁵

f = ?

f = 1.86 x 10⁵ / 6.7 x 10⁻⁷

f = 2.78 x 10¹¹Hz

<h3>Frequency :</h3>

The number of waves that pass a fixed place in a unit of time is referred to as frequency. It also indicates how many cycles or vibrations a body in periodic motion experiences in a given unit of time. The formula for frequency expressed in terms of time is given as follows: f = 1/T, where f is the frequency expressed in hertz and T is the duration of one cycle expressed in seconds.

To know more about waves :

brainly.com/question/19477984

#SPJ1

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Answer:

Peptide bonds form from nucleophilic attack by an α‑carboxyl carbon atom on an electron pair of an α‑amino nitrogen atom of another amino acid.

Explanation:

Peptide bond is a form of covalent bond and it is Amide type that is formed between two molecules when carboxyl group react with one molecule of amino group to release molecule of water.The peptide bond are in form pseudo-double bond characteristic; rigid, planar, and stronger than a typical Carboxyl nitrogen single bond.

Peptide bonds form from nucleophilic attack by an α‑carboxyl carbon atom on an electron pair of an α‑amino nitrogen atom of another amino acid.

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one of the isotopes of sulfur is represented as sulfur -35 or S-35. what does the number 35 signify?
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6 0
4 years ago
Read 2 more answers
PLZ HELP ...The half-life of polonium-218 is 3.0 minutes. If you start with 40.0 g, how long will it be before only 4.5 g remain
Elanso [62]

Answer:-  9.4 minutes.

Solution:- Radioactive decay obeys first order reaction kinetics and the equation used to solve this type of problems is:

lnN=-kt+lnN_0

where, k is decay constant and t is the time. N_0 is the initial amount of the radioactive substance and N is the remaining amount.

Since the value of decay constant is not given, so we need to calculate it first from given half life by using the formula:

k=\frac{0.693}{t_1_/_2}

where t_1_/_2 stands for half life.

Given half life is 3.0 minutes.

So, k=\frac{0.693}{3.0min}

k=0.231min^-^1

Let's plug in the values in the first order reaction equation and solve it for t.

ln4.5g=-0.231min^-^1(t)+ln40.0g

It could also be written as:

ln(\frac{4.5g}{40.0g})=-0.231min^-^1}

-2.18=-0.231min^-^1}

t=\frac{-2.18}{-0.231min^-^1}

k = 9.4 min

So, the radioactive substance would take 9.4 minutes to decay from 40.0 grams to 4.5 grams.

4 0
3 years ago
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