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gayaneshka [121]
1 year ago
15

What is the value of the expression 1.6(x−y)2 when x = 10 and y = 5?

Mathematics
2 answers:
Luba_88 [7]1 year ago
7 0

Answer:

1.6(10-5)2= 1.6(5)2= (8)(2)=16

Step-by-step explanation:

Deffense [45]1 year ago
7 0

Answer:

40

Step-by-step explanation:

<h3>Finding the value of expression:</h3>

     Substitute x = 10 and y = 5 in the expression.

1.6(x - y)² = 1.6(10 - 5)²

               = 1.6 * (5)²

               = 1.6 * 25

               = 40

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Answer:

B. The other solution to function h is -4-i\,7.

Step-by-step explanation:

From Algebra, we remember that quadratic functions of the form a\cdot x^{2}+b\cdot x + c has solutions of the form:

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3 years ago
The graph shows Marcia's walk. Which statement best describes what Marcia could be doing on the interval from B to C? A. Marcia
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Step-by-step explanation:

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Find the length of the curve y = 3/5x^5/3 - 3/4x^1/3 + 6 for 1 &lt; = x &lt; = 8. The length of the curve is . (Type an exact an
Mashutka [201]

Answer:

\sqrt\frac{387}{20}

Step-by-step explanation:

Arc Length =\int\limits^a_b {\sqrt{1+(\frac{dy}{dx})^2 } } \, dx

y=\dfrac{3}{5}x^{\frac{5}{3}}-  \dfrac{3}{4}x^{\frac{1}{3}}+6

\frac{dy}{dx} =x^{\frac{2}{3}}-\dfrac{1}{4}x^{-\frac{2}{3}}

1+(\frac{dy}{dx})^2 }=1+(x^{\frac{2}{3}}-\dfrac{1}{4}x^{-\frac{2}{3}})^2\\=1+(x^{\frac{4}{3}}-\dfrac{1}{2}+ \dfrac{1}{16}x^{-\frac{4}{3}})

=\dfrac{1}{2}+x^{\frac{4}{3}}+ \dfrac{1}{16}x^{-\frac{4}{3}}

For the Interval 1\leq x\leq 8

Length of the Curve =\int\limits^8_1 {\sqrt{\dfrac{1}{2}+x^{\frac{4}{3}}+ \dfrac{1}{16}x^{-\frac{4}{3}} } } \, dx\\

Using T1-Calculator

=\sqrt\frac{387}{20}

3 0
3 years ago
The base of an isosceles tiangle has a length of 25. what can you say about the lengths of the legs?
lidiya [134]
The sum of the lengths of any two sides of a triangle must be greater than the length of the third side (or else, it can't be a closed polygon). Since we know that the two sides in question are both of the same length in this case (since the triangle isosceles), their individual lengths must be greater than 25/2 = 12.5.
7 0
3 years ago
Suppose that the bacteria in a colony grow unchecked according to the Law of Exponential Change. The colony starts with 1 bacter
inn [45]

Answer: There are 2.25×10³⁴ bacteria at the end of 24 hours.

Step-by-step explanation:

Since we have given that

Number of bacteria initially = 1

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So, \dfrac{20}{60}=\dfrac{1}{3}

So, our equation becomes

y=y_0e^{\frac{1}{3}k}\\\\3=1e^{\frac{1}{3}k}\\\\\ln 3=\dfrac{1}{3}k\\\\k=\dfrac{1.099}{0.333}=3.3

We need to find the number of bacteria that it will contain at the end of 24 hours.

So, it becomes,

y=1e^{24\times 3.3}\\\\y=e^{79.1}\\\\y=2.25\times 10^{34}

Hence, there are 2.25×10³⁴ bacteria at the end of 24 hours.

3 0
2 years ago
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