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Wittaler [7]
3 years ago
5

A 2.26 M solution of KOH is prepared. Calculate the moles and mass of solute present in a 15.2-mL sample of this solution. The m

olar mass of KOH is 56.11 g/mol.
Chemistry
1 answer:
kenny6666 [7]3 years ago
7 0

Answer:

0.0344 moles and 1.93g.

Explanation:

Molarity is defined as the ratio between moles of a solute (In this case, KOH), and the volume. With molarity and volume we can solve the moles of solute. With moles of solute we can find mass of the solute as follows:

<em>Moles KOH:</em>

15.2mL = 0.0152L * (2.26mol / L) = 0.0344moles

<em>Mass KOH:</em>

0.0344 moles * (56.11g/mol) = 1.93g of KOH

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<u>Answer:</u>

<u>For Part A:</u> The partial pressure of Helium is 218 mmHg.

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<u>Explanation:</u>

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We are given:

p_{CO_2}=245mmHg\\p_Ar}=119mmHg\\p_{O_2}=163mmHg\\P=745mmHg

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Putting values in above equation, we get:

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