A sample of iron absorbs 67.5 j of heat upon which the temperature of the sample increases from 21.5 °c to 28.5 °c. if the speci fic heat of iron is 0.450 j/g-k, what is the mass (in grams) of the sample?
2 answers:
Answer : The mass of the sample is, 21.428 grams.
Solution :
Formula used :
where,
Q = heat absorbs = 67.5 J
m = mass of sample = ?
c = specific heat of iron =
= final temperature =
= initial temperature =
Now put all the given values in the above formula, we get the mass of the sample.
Therefore, the mass of the sample is, 21.428 grams
Q = mcΔθ 67.5 = m x 0.45 x (28.5 - 21.5) M = 67.5 / 3.15 = 21.4 g
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