this is so ez,
ok so here what u'll do after u balance the equation:
1. convert grams of oxygen to moles of oxygen.
2. convert moles of oxygen to moles of water
3. convert moles of water to grams of water.
4. bOOm... that's your answer
as follows:
2H2O(l)===>2H2(g)+O2(g)
1. 151200(g)/16(g/mol)=9540 moles of O2
2. 9450 moles of O2 × 2 moles of H2O =18900 moles of H2O
3. 18900 moles of H2O × 10g/mol = 189000g of H2O is required.
Answer:23.9 g
Explanation:
Grams C = (12/6.02214076)*12 = 23.9 g
Answer:
3 valence electrons
Explanation:
There are only 5 electrons in the outer shell of Cesium so it needs to gain 3 to become stable. The number of electrons an atom needs to lose or gain to become stable is the same as the number of valence electrons. Therefore, the answer is 3.
For this question, we assume the gas is an ideal gas so that we could use a simpler equation which is the ideal gas equation. It is expressed as:
PV = nRT
P = nRT / V
P = 35/28 (0.08206) (273.15) / .195
P = 143.68 atm
Hope this answers the question. Have a nice day.