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Nostrana [21]
1 year ago
10

Determine the instantaneous rate of change without using derivatives please

Mathematics
1 answer:
Fittoniya [83]1 year ago
5 0

we have the function

f(x)=\frac{x}{x-2}

To find out the instantaneous rate of change without using derivatives, we need two points

For x=0

f(0)=\frac{0}{0-2}=0

The first point is (0,0)

For x=-1

f(-1)=\frac{-1}{-1-2}=\frac{1}{3}

The second point is (-1,1/3)

Find out the slope

\begin{gathered} m=\frac{\frac{1}{3}-0}{-1-0} \\  \\ m=-\frac{1}{3} \end{gathered}

therefore

<h2>The instantaneous rate of change is -0.33</h2>

Verify the answer with the exact answer (with derivative)

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Please help!!<br> I’m so confused <br> And please don’t use the link joke
bagirrra123 [75]

Answer:

15u + 141 = 420

Step-by-step explanation:

So basically we are modelling how much the coach is spending. Each player is given a uniform and a basketball

We can use 'u' as the cost of a single uniform

We can use 'b' as the cost of a single basketball

Since there is 15 players we must give a ball and uniform to each so

15u + 15b = 420

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The numbers​ 1, 2,​ 3, 4, and 5 are written on slips of​ paper, and 2 slips are drawn at random one at a time without replacemen
mamaluj [8]
<h2>Answer:</h2>

(a)

The probability is :  1/2

(b)

The probability is :  1/2

<h2>Step-by-step explanation:</h2>

The numbers​ 1, 2,​ 3, 4, and 5 are written on slips of​ paper, and 2 slips are drawn at random one at a time without replacement.

The total combinations that are possible are:

(1,2)   (1,3)    (1,4)    (1,5)

(2,1)   (2,3)   (2,4)   (2,5)

(3,1)   (3,2)   (3,4)   (3,5)

(4,1)   (4,2)   (4,3)   (4,5)

(5,1)   (5,2)   (5,3)   (5,4)

i.e. the total outcomes are : 20

(a)

Let A denote the event that the first number is 4.

and B denote the event that the sum is: 9.

Let P denote the probability of an event.

We are asked to find:

               P(A|B)

We know that it could be calculated by using the formula:

P(A|B)=\dfrac{P(A\bigcap B)}{P(B)}

Hence, based on the data we have:

P(A\bigcap B)=\dfrac{1}{20}

( Since, out of a total of 20 outcomes there is just one outcome which comes in A∩B and it is:  (4,5) )

and

P(B)=\dfrac{2}{20}

( since, there are just two outcomes such that the sum is: 9

(4,5) and (5,4) )

Hence, we have:

P(A|B)=\dfrac{\dfrac{1}{20}}{\dfrac{2}{20}}\\\\i.e.\\\\P(A|B)=\dfrac{1}{2}

(b)

Let A denote the event that the first number is 3.

and B denote the event that the sum is: 8.

Let P denote the probability of an event.

We are asked to find:

               P(A|B)

Hence, based on the data we have:

P(A\bigcap B)=\dfrac{1}{20}

( since, the only outcome out of 20 outcomes is:  (3,5) )

and

P(B)=\dfrac{2}{20}

( since, there are just two outcomes such that the sum is: 8

(3,5) and (5,3) )

Hence, we have:

P(A|B)=\dfrac{\dfrac{1}{20}}{\dfrac{2}{20}}\\\\i.e.\\\\P(A|B)=\dfrac{1}{2}

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3 years ago
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baherus [9]

Answer:

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Step-by-step explanation:

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