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2 years ago

The phase change that occurs when a liquid goes to a gas?

Chemistry

2 answers:

jek_recluse [69]2 years ago

8 0

The person above is correct

Lana71 [14]2 years ago

5 0

Vaporization:--- Vaporization is a phase transition from the liquid phase to the gas phase.

When a liquid changes to gas, the particles absorb heat energy and they start vibrating faster and distance between them increases. On constant vibration, intermolecular forces decrease and particles start moving away from each other and change to gas

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By which process is a precipitate most easily separated from the liquid in which it is suspended

Gelneren [198K]

<span>Filtration, if its a precipitate that means its insoluble. </span>

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3 years ago

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Suppose a tank contains 100 gallons of a solution of 10 lb of salt dissolved in water, which is kept uniform by stirring. Pure

kupik [55]

Answer:

Please see attachment

Explanation:

Please see attachment

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3 years ago

How much pressure would 0.8 moles of a gas at 370K exert if it occupied 17.3L of space

dezoksy [38]

Answer:

1.40 atm is the pressure for the gas

Explanation:

An easy problem to solve with the Ideal Gases Law:

P . V = n . R .T

T° = 370K

V = 17.3L

n = 0.8 mol

Let's replace data → P . 17.3L = 0.8mol . 0.082L.atm/mol.K . 370K

P = (0.8mol . 0.082L.atm/mol.K . 370K) / 17.3L = 1.40 atm

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3 years ago

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The standard cell potential (E°cell) for the reaction below is +0.63 V. The cell potential for this reaction is ________ V when

tia_tia [17]

Answer : The cell potential for this reaction is 0.50 V

Explanation :

The given cell reactions is:

$Pb^{2+}(aq)+Zn(s)\rightarrow Zn^{2+}(aq)+Pb(s)$

The half-cell reactions are:

Oxidation half reaction (anode): $Zn\rightarrow Zn^{2+}+2e^-$

Reduction half reaction (cathode): $Pb^{2+}+2e^-\rightarrow Pb$

First we have to calculate the cell potential for this reaction.

Using Nernest equation :

$E_{cell}=E^o_{cell}-\frac{2.303RT}{nF}\log \frac{[Zn^{2+}]}{[Pb^{2+}]}$

where,

F = Faraday constant = 96500 C

R = gas constant = 8.314 J/mol.K

T = room temperature = $25^oC=273+25=298K$

n = number of electrons in oxidation-reduction reaction = 2

$E^o_{cell}$ = standard electrode potential of the cell = +0.63 V

$E_{cell}$ = cell potential for the reaction = ?

$[Zn^{2+}]$ = 3.5 M

$[Pb^{2+}]$ = $2.0\times 10^{-4}M$

Now put all the given values in the above equation, we get:

$E_{cell}=(+0.63)-\frac{2.303\times (8.314)\times (298)}{2\times 96500}\log \frac{3.5}{2.0\times 10^{-4}}$

$E_{cell}=0.50V$

Therefore, the cell potential for this reaction is 0.50 V

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3 years ago

What form of matter has a definite shape and takes up space?

BARSIC [14]

Answer:

If something is in a solid state of matter, it has a definite shape and volume. The volume of an object is the amount of space it occupies. A block of wood placed on a table retains its shape and volume, therefore, it is an example of a solid. If a liquid is poured on that same table, there are very different results

Explanation:

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3 years ago

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