Answer:
Molar mass of NaN3,
MM = 1*MM(Na) + 3*MM(N)
= 1*22.99 + 3*14.01
= 65.02 g/mol
mass of NaN3 = 1.3*10^2 g
mol of NaN3 = (mass)/(molar mass)
= 1.3*10^2/65.02
= 2.0 mol
Balanced chemical equation is:
2NaN3(s) ---> 2Na(s) + 3N2(g)
According to balanced equation
mol of N2 formed = (3/2)* moles of NaN3
= (3/2)*2.0
= 3.0 mol
Molar mass of N2 = 28.02 g/mol
mass of N2 = number of mol * molar mass
= 3.0*28.02
= 84.0 g
Now use:
density = mass / volume
0.916 g/L = 84.0 g / volume
volume = 91.7 g
Answer: 91.7 g
