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3 years ago

Is there are 10.0 g of sucrose and 8.0 g of oxygen, how many moles of sucrose are available for this reaction

Chemistry

2 answers:

liq [111]3 years ago

8 0

If there is a multiple choice then the answer would be 0.029. I hope this helps you

katrin2010 [14]3 years ago

7 0

Answer:

There are 0.0292 moles of sucrose available for this reaction

Explanation:

Number of moles of a compound = $\frac{mass of compound}{molar mass of the compound}$

Here mass of sucrose is 10.0 g. Molar mass of sucrose is 342.3 g/mol

So moles of sucrose available for this reaction = $\frac{10 g}{342.3 g/mol}= 0.0292 moles$

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How many atoms of oxygen are in 0.100 mol of silicon dioxide?

lys-0071 [83]

1) Silicon dioxide formula: SiO2 ....... 2 is a subscript for the O atom

2) From the formula you have 1 molecula of SiO2 contains 1 atom of SiO2

3) Then, 0.100 mol of SiO2 contains 0.1 mol of Si

4) Multiply by Avogadro's number: 0.100mol * 6.022*10^23 atoms/mol= 6.02*10^22 atoms

Answer: 6.02*10^22 atoms

3 0

3 years ago

the gas left in an used aerosol can is at a pressure of 103 kPa at 25 degrees celsius if this can be thrown into fire what is th

Rainbow [258]

Hello!

The pressure of the gas when it's temperature reaches 928 °C is 3823,36 kPa

To solve that we need to apply Gay-Lussac's Law. It states that the pressure of a gas when the volume is left constant (like in the case of a sealed container like an aerosol can) is proportional to temperature. This is the relationship derived from this law that we use to solve this problem:

$P2= \frac{P1}{T1}*T2= \frac{103 kPa}{25}*928=3823,36 kPa$

Have a nice day!

5 0

3 years ago

Read 2 more answers

Review the equation below. 2KClO3 mc012-1.jpg 2KCl + 3O2 How many moles of oxygen are produced when 2 mol of potassium chlorate

Vlada [557]

Stoichiometry <span>of the reaction:

</span><span>2 KClO</span>₃<span>   =   2 KCl + 3 O</span>₂
  ↓ ↓

2 mole KClO₃ ----------> 3 mole O₂
2 mole KClO₃ ----------> ?

KClO₃ = 2 * 3 / 2

KClO₃ = 6 / 2

= 3 moles de KClO₃

hope this helps!

4 0

3 years ago

Read 2 more answers

I will mark brainliest

Veronika [31]

I believe the answer is B??????????? Hope this helps

~Queensupreme

5 0

3 years ago

Read 2 more answers

A solution consists of 35.00 g of CuSO4 dissolved in 250.0 mL of water. The molar mass of Cu is 63.55 g/mol the molar mass of S

slamgirl [31]

The molarity of a solution that contains 35.00 g of CuSO4 dissolved in 250.0 mL of water is 0.88M.

<h3>How to calculate molarity?</h3>

The molarity of a solution can be calculated using the following formula:

Molarity = no of moles/volume

According to this question, a solution consists of 35.00 g of CuSO4 dissolved in 250.0 mL of water.

no.of moles of CuSO4 = 35g ÷ 159.6g/mol

no. of moles of CuSO4 = 0.22 moles

Therefore; molarity of CuSO4 solution is calculated as follows:

M = 0.22 ÷ 0.25

M = 0.88M

Therefore, the molarity of a solution that contains 35.00 g of CuSO4 dissolved in 250.0 mL of water is 0.88M.

Learn more about molarity at: brainly.com/question/12127540

6 0

2 years ago