Answer: Escaped volume = 0.0612m^3
Explanation:
According to Boyle's law
P1V1 = P2V2
P1 = initial pressure in the tire = 36.0psi + 14.696psi = 50.696psi (guage + atmospheric pressure)
P2 = atmospheric pressure= 14.696psi
V1 = volume of tire =0.025m^3
V2 = escaped volume + V1 ( since air still remain in the tire)
V2 = P1V1/P2
V2 = 50.696×0.025/14.696
V2 = 0.0862m^3
Escaped volume = 0.0862 - 0.025 = 0.0612m^3
PE = mass * height * 9.81
PE = 142 * 25 * 9.81
PE = 34825.5 J
Explanation:
Given that,
Force, 
Position of the particle, 
(a) The toque on a particle about the origin is given by :


Taking the cross product of above two vectors, we get the value of torque as :

(b) Let
is the angle between r and F. The angle between two vectors is given by :



