Answer:
A 5.00-g bullet is fired horizontally into a 1.20-kg wooden block resting on a horizontal surface. The coefficient of kinetic friction between block and surface is 0.20. The bullet remains embedded in the block, which is observed to slide 0.230 m along the surface before stopping.
Explanation:
The acceleration when a 60 kg man in bosun's chair exerts a pull, is -3.76 m/s².
<h3>What is acceleration?</h3>
The acceleration is the time rate of change of velocity.
Given the mass of man m= 60 kg and pull = 363N
According to the equilibrium conditions, 3T -mg =ma
The pull is equal to the tension 3T =363 N
Substituting the values, we get
363N - 60x 9.81 = 60a
a =-3.76m/s²
Thus, the acceleration is -3.76m/s².
Learn more about Acceleration.
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F = m * a
F = 15 kg * 8 m/s²
F = 120 N
Answer B
hope this helps
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Answer:
a) 5.63 atm
Explanation:
We can use combined gas law
<em>The combined gas law</em> combines the three gas laws:
- Boyle's Law, (P₁V₁ =P₂V₂)
- Charles' Law (V₁/T₁ =V₂/T₂)
- Gay-Lussac's Law. (P₁/T₁ =P₂/T₂)
It states that the ratio of the product of pressure and volume and the absolute temperature of a gas is equal to a constant.
P₁V₁/T₁ =P₂V₂/T₂
where P = Pressure, T = Absolute temperature, V = Volume occupied
The volume of the system remains constant,
So, P₁/T₁ =P₂/T₂
a) 
