Answer:

Explanation:
Radioactive decay behaves according to the law of exponential decay:

Where:




So we need to find the decay rate r. Let's find it using the equation and the data provide, but first, we need to convert the hours in days:

Now for
then:

Divide both sides by 100:

Take the natural logarithm of both sides:

Multiply both sides by -8/11:

Now we have found the rate decay r, let's find how many milligrams will remain after 59 hours (25/12 day):

A battery operated lamp because battery's don't use your own electricity. They come with electricity already.
<h3><u>Given </u><u>:</u><u>-</u></h3>
- The mass of the body is doubled
- The height of the body is constant
<h3><u>Solution </u><u>:</u><u>-</u><u> </u></h3>
We know that ,
Potential energy = mgh
<u>Therefore</u><u>, </u>
We can say that,
PE is directly proportional to Mass of the body
<u>According </u><u>to </u><u>the </u><u>question</u><u>, </u>
PE of the body = 2m * g * h. ...eq( I)
From (I) , we can conclude that, If mass of the body get doubled then its PE will also be doubled .
Answer:
Explanation:
Given that on the tree the gravitational energy stored is 8J
Then, mgh = 8J.
The apple begins to fall and hit the ground, what is the maximum kinetic energy?
Using conservation of energy, as the above is about to hit the ground, the apple is at is maximum speed, and the height then is 0m, so the potential energy at the ground is zero, so all the potential of the apple at the too of the tree is converted to kinetic energy as it is about to hits the ground. Along the way to the ground, both the Kinetic energy and potential energy is conserved, it is notice that at the top of the tree, the apple has only potential energy since velocity is zero at top, and at the bottom of the tree the apple has only kinetic energy since potential energy is zero(height=0)
So,
K.E(max) = 8J
Answer: I would say static electricity.
Explanation: