Answer:
The value is ![u_x = 597 \ m/s](https://tex.z-dn.net/?f=u_x%20%3D%20%20597%20%5C%20%20m%2Fs)
Explanation:
From the question we are told that
The distance of the target from the riffle is
The height at which the bullet hit the target is ![y = 2.2 \ cm = 0.022 \ m](https://tex.z-dn.net/?f=y%20%3D%20%202.2%20%5C%20%20cm%20%3D%20%200.022%20%5C%20m)
Considering the vertical motion
Generally from kinematic equations we have that
![y = u_y t + \frac{1}{2} * gt^2](https://tex.z-dn.net/?f=y%20%3D%20%20u_y%20t%20%2B%20%20%5Cfrac%7B1%7D%7B2%7D%20%2A%20gt%5E2)
At the initial stage the velocity is zero i.e ![u_y = 0 \ m/s](https://tex.z-dn.net/?f=u_y%20%20%3D%20%200%20%5C%20m%2Fs)
=>
=> ![t = 0.067 \ s](https://tex.z-dn.net/?f=t%20%3D%20%200.067%20%5C%20%20s)
Generally the velocity of the bullet when it leaves the riffle is mathematically represented as
![u_x = \frac{ d}{t}](https://tex.z-dn.net/?f=u_x%20%3D%20%20%5Cfrac%7B%20d%7D%7Bt%7D)
=> ![u_x = \frac{40 }{ 0.067 }](https://tex.z-dn.net/?f=u_x%20%3D%20%20%5Cfrac%7B40%20%7D%7B%200.067%20%7D)
=> ![u_x = 597 \ m/s](https://tex.z-dn.net/?f=u_x%20%3D%20%20597%20%5C%20%20m%2Fs)
Disagree.
Fluoresce objects will only glow when put under actual Ultraviolet light. This is due to the molecules becoming excited by the ultraviolet radiation.
Microwaves give micro-waves that are present in another spectrum of wave length and will not be able to fluoresce the molecules. If it’s not “ultra violet “.... it’s not going to glow.
Answer:
30.9 m
Explanation:
x = 129.9 m y = 30.9 m First of all, let's calculate the horizontal and vertical velocities involved h = 50.0cos(30) = 43.30127 m/s v = 50.0sin(30) = 25 m/s The horizontal distance is simply the horizontal velocity multiplied by the time, so 43.30127 m/s * 3 s = 129.9 m So the horizontal distance traveled is 129.9 m, so x = 129.9 m The vertical distance needs to take into account gravity which provides an acceleration of -9.8 m/s^2, so we get d = 25 m/s * 3s - 0.5*9.8 m/s^2 * (3 s)^2 d = 75 m - 4.9 m/s^2 * 9 s^2 d = 75 m - 44.1 m d = 30.9 m So the vertical distance traveled is 30.9 m, so y = 30.9 m
Alpacas were used for their meat, fibers for clothing, and art, and their images in the form of conopas.
The magnitude of the vector C is 96.32m
<h3>How to solve for the magnitude of vector c</h3>
Ax = AcosθA
= 40 cOS 20
= 37.59
Ay = AsinθA
-40sin20
= -13.68
Bx = B cos θ B
= 75Cos50
= 48.21
By = BsinθB
= 75sin50
= 57.45
Cx = AX + Bx
= 37.59 + 48.21
= 85.8
Cy = Ay + By
= -13.65 + 57.45
= 43.77
The magnitude is solved by
|c| = ![\sqrt{Cx^{2}+Cy^{2} }](https://tex.z-dn.net/?f=%5Csqrt%7BCx%5E%7B2%7D%2BCy%5E%7B2%7D%20%20%7D)
= √85.8² + 43.77²
= 96.32m
The magnitude of the vector c is 96.32m
Read more on the magnitude of a vector here:
brainly.com/question/3184914
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