Assume a normal distribution and that the average phone call in a certain town lasted 4 min, with a standard deviation of 1 min.
1 answer:
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Answer:
The complete question in the graphic
A.
After synchronized exercise, it was observed that the average proximity rate has increased, which shows that the mean of the variable is positive and there is high synchronization in the groups.
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B.
If groups with low synchronization and high effort are compared, the result of the average will be positive, so the average proximity rate will also increase after the synchronization exercise is performed.
On the contrary, if we observe the groups that have low synchronization and low effort, the mean of the variable is negative, thus the average proximity rate after performing the exercise will decrease.
(C)
considering that the total degrees of freedom is 259, it will show 260 students in the analysis.
D.
With a significance level of 5% or 0.05, the P value is less than the significance level, which leads to differentiating the mean of the scores before and after performing the combinations.
E.
With a significance level of 1% or 0.01, the p-value is higher than the significance level. With this data we can conclude that there is no difference between the results before and after the synchronized exercise
