The outliers of a boxplot are data points that are not in the whiskers of the boxplot
The given parameters are:
<u>Male do gs</u>
- Minimum = 0
- Lower quartile, Q1 = 3
- Median, Q2 = 10
- Upper quartile, Q3 = 15
- Maximum = 35.
<u>Female do gs</u>
- Minimum = 0
- Lower quartile, Q1 = 2
- Median, Q2 = 6
- Upper quartile, Q3 = 9
- Maximum = 14
- Outlier = 31.
<h3>Part A: The IQR for the male's data</h3>
This is calculated as:

So, we have:


Hence, the IQR for the male's data is 12
<h3>Part B: The difference in their median</h3>
This is calculated as:

So, we have:


Hence, the difference between the median value of each data is 4
<h3>Part C: The distribution of the data</h3>
The distribution of the male's data is not affected by outlier, while the distribution of the female's data is affected by outlier
Hence, the mean is a better measure of center for the male's distribution while the median is a better measure of center for the female's distribution
<h3>Part D: Reason for outlier</h3>
The possible reason for the outlier in the dataset could be as a result of natural variation in the breeds
Read more about boxplots and outliers at:
brainly.com/question/14277132
Answer:
5 3/4
Step-by-step explanation:
I say this because...
9-3= 6 and 4/4 -1/4 equals 3/4 so you take the whole that was 6 and put 5 since you took 1/4 out of the whole number
Probability(both marbles are red) = 5/12 * 4/11 = 20/132
= 5/33 Answer
Got chu fam, the answer is 5/21