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kaheart [24]
3 years ago
11

What is 7/x-3/2=n-mx/px​

Mathematics
1 answer:
andriy [413]3 years ago
8 0

Answer:

answer is 1=2=3244515/15/152/51//51/1=12900 is  the answer all you need to do is get 1700k - 10000 and yes its negative.

Step-by-step explanation:

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One number is 2 less than a second number. twice the second number is 16 more than 4 times the first. find the two numbers.
Nostrana [21]
Let the numbers be x and y

x= y-2.... (1)
and, 2y = 16 + 4x.... (2)

putting the value of x from (1) in (2),

2y = 16 + 4x
=> 2y = 16 + 4(y-2)
=> 2y = 16 + 4y - 8
=> 2y = 8 + 4y
=> 2y - 4y = 8
=> -2y = 8
=> y =-8/2
=> y= -4

and x = -4-2 = -6

hence , in short the numbers are -2 and -4



4 0
3 years ago
PLS HELP!!
irina [24]
$789.18 * 0.062 = $48.93
answer is <span>48.93 (first choice)</span>
8 0
4 years ago
Read 2 more answers
ariana's 150g bag of trail mix is x% raisins. brandon's 250g bag of trail mix is y% raisins. they combine the two mixes together
Tema [17]

Answer:

(3x+5y)/8

Step-by-step explanation:

The total amount is 150+250=400

We then do (3x+5y)/2 × 1/400

This equals (3x+5y)/800

We multiply that  by 100 giving us the final answer.

7 0
3 years ago
Suppose a shoe factory produces both low-grade and high-grade shoes. The factory produces at least twice as many low-grade as hi
umka2103 [35]

Answer:

The factory should produce 166 pairs of high-grade shoes and 364 pairs of low-grade shoes for maximum profit

Step-by-step explanation:

The given parameters for the shoe production are;

The number of low grade shoes the factory produces ≥ 2 × The number of high-grade shoes produced by the factory

The maximum number of shoes the factory can produce = 500 pairs of shoes

The number of high-grade shoes the dealer calls for daily ≥ 100 pairs

The profit made per pair of high-grade shoed = Birr 2.00

The profit made per of low-grade shoes = Birr 1.00

Let 'H', represent the number of high grade shoes the factory produces and let 'L' represent he number of low-grade shoes the factory produces, we have;

L ≥ 2·H...(1)

L + H ≤ 500...(2)

H ≥ 100...(3)

Total profit, P = 2·H + L

From inequalities (1) and (2), we have;

3·H ≤ 500

H ≤ 500/3 ≈ 166

The maximum number of high-grade shoes that can be produced, H ≤ 166

Therefore, for maximum profit, the factory should produce the maximum number of high-grade shoe pairs, H = 166 pairs

The number of pairs of low grade shoes the factory should produce, L = 500 - 166 = 334 pairs

The maximum profit, P = 2 × 166 + 1 × 364 = 696

6 1
3 years ago
Read 2 more answers
Round 3,567 to the nearest ten​
WINSTONCH [101]

Answer:3,570

Step-by-step explanation: The 7 is over 5 so u know, 5 or more up the score. 4 percent or less let it rest.

8 0
4 years ago
Read 2 more answers
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