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Artemon [7]
1 year ago
3

the board sandwiched between two other boards shown below weighs 84.5 n. if the coefficient of friction between the boards is 0.

522, what must be the magnitude of the compression forces (assume horizontal) acting on both sides of the center board to keep it from slipping?
Physics
1 answer:
lianna [129]1 year ago
7 0

The magnitude of the compression forces acting on both sides of the center board to keep it from slipping is 80.94 N

f = μ N

f = Frictional force

μ = Coefficient of friction

N = Normal force

μ = 0.522

W = 84.5 N

The normal forces are the compression forces acting on both sides of the center board that keeps it from slipping

To keep the center board from slipping,

∑Fy = 0

f + f - W = 0

2 f - W = 0

2 μ N - W = 0

( 2 * 0.522 * N ) = 84.5

1.044 N = 84.5

N = 80.94 N

Therefore, the magnitude of the compression forces acting on both sides of the center board to keep it from slipping is 80.94 N

To know more about Frictional force

brainly.com/question/14935759

#SPJ4

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