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Oksi-84 [34.3K]
3 years ago
8

I will thank and give 5 stars to whoever answers!!

Physics
2 answers:
uranmaximum [27]3 years ago
7 0

Answer:

1.moon

2.Earth is the first planet with a satellite, or moon.

3.Mars, the fourth planet out, has two moons, but they are probably just a couple of big old rocks.

5.The incoming object was destroyed on impact, reduced to vapor, dust, and chunks. Large surviving parts were driven deep into the interior of Earth. A signicant portion of Earth was destroyed as well. The energy that resulted from the crash produced an explosion of unimaginable magnitude.

Explanation:

i did what i can

worty [1.4K]3 years ago
4 0

Answer:

1.moon

2.Earth is the first planet with a satellite, or moon.

3.Mars, the fourth planet out, has two moons, but they are probably just a couple of big old rocks.

5.The incoming object was destroyed on impact, reduced to vapor, dust, and chunks. Large surviving parts were driven deep into the interior of Earth. A signicant portion of Earth was destroyed as well. The energy that resulted from the crash produced an explosion of unimaginable magnitude.

Explanation:

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3 0
3 years ago
Read 2 more answers
A train on a straight track goes in the positive direction for 5.9 km, and then backs up for 3.8 km
kenny6666 [7]

Answer:

2.1km

Explanation:

Ill take it as u are talking about the displacement

Since displacement has negatives and positves

5.9 - 3.8 = 2.1km

6 0
3 years ago
A 62 kg skier is moving at 6.5 m/s on frictionless horizontal snow-covered plateau when she encounters a rough patch 3.50 m long
Degger [83]

Answer:

(A). The work done by friction in crossing the patch is -637.98 J.

(B). The speed of skier is 10.57 m/s.

Explanation:

Given that,

Mass of skier = 62 kg

Speed = 6.5 m/s

Length = 3.50 m

Coefficient kinetic friction = 0.30

Height = 2.5 m

(A) we need to calculate the work done by friction in crossing the patch

Using formula of work done

W=-\mu mg\times l

Put the value into the formula

W=-0.30\times62\times9.8\times3.50

W=-637.98\ J

The work done by friction in crossing the patch is -637.98 J.

(B) we need to calculate the speed of skier

Using conservation of energy

K.E_{i}+U_{i}-W_{friction}=K.E_{f}+U_{f}

\dfrac{1}{2}mv_{1}^2+mgh-\mu mgl=\dfrac{1}{2}mv_{2}^2+U_{f}

Final potential energy is zero

So, \dfrac{1}{2}mv_{1}^2+mgh-\mu mgl=\dfrac{1}{2}mv_{2}^2

\dfrac{1}{2}v_{2}^2=\dfrac{1}{2}v_{1}^2+gh-\mu gl

Put the value into the formula

\dfrac{1}{2}v_{2}^2=\dfrac{1}{2}\times6.5^2+9.8\times2.5+0.30\times9.8\times3.50

v_{2}=\sqrt{2\times55.915}

v_{2}=10.57\ m/s

The speed of skier is 10.57 m/s.

Hence,  (A).The work done by friction in crossing the patch is -637.98 J.

(B).The speed of skier is 10.57 m/s.

6 0
3 years ago
Which question requires the collection of data to answer it?
iren [92.7K]

Answer:

a

Explanation:

b, c, and d are all opinion based, a is the only one that you need factual evidence and observations.

3 0
3 years ago
Hi guys! :) I really need help on this!! Will def mark brainliest
Travka [436]

Wavelength = (speed) / (frequency)

Speed of radio = speed of light.

3 0
3 years ago
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