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2 years ago

I will thank and give 5 stars to whoever answers!!

Physics

2 answers:

uranmaximum [27]2 years ago

7 0

Answer:

1.moon

2.Earth is the first planet with a satellite, or moon.

3.Mars, the fourth planet out, has two moons, but they are probably just a couple of big old rocks.

5.The incoming object was destroyed on impact, reduced to vapor, dust, and chunks. Large surviving parts were driven deep into the interior of Earth. A signicant portion of Earth was destroyed as well. The energy that resulted from the crash produced an explosion of unimaginable magnitude.

Explanation:

i did what i can

worty [1.4K]2 years ago

4 0

Answer:

1.moon

2.Earth is the first planet with a satellite, or moon.

3.Mars, the fourth planet out, has two moons, but they are probably just a couple of big old rocks.

Explanation:

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What is a substance

Korolek [52]

Explanation:

A particular kind of matter with uniform properties..

8 0

3 years ago

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What is the maximum range of most handheld fire extinguishers? A. 50 yd B. 30 ft C. 10 ft D. 100 ft

alex41 [277]

C- 10ft. Hope this helped. Have a great day! :D

5 0

3 years ago

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A crane lifts a load of 15000N to a height 40m in 50 seconds. Calculate the power of the crane

Nataly [62]

Answer:

P = 12000 W

Explanation:

General data:

F = 15000 N
d = 40 m
t = 50 s
P = ?

Work is force times unit of distance. So in order to calculate the power we must first calculate the work.

Formula:

$\boxed{\bold{W=\frac{F}{d}}}$

Replace and solve

$\boxed{\bold{W=\frac{15000\ N}{40\ m}}}$

$\boxed{\bold{W=600000\ J}}$

once the work is found, we proceed to find the power according to the formula:

$\boxed{\bold{P=\frac{W}{t}}}$

$\boxed{\bold{P=\frac{600000\ J}{50\ s}}}$

$\boxed{\boxed{\bold{P=12000\ W}}}$

The power of the crane is <u>12000 Watts.</u>

Greetings.

6 0

2 years ago

. One long wire carries a current of 30 A along the entire x axis. A second-long wire carries a current of 40 A perpendicular to

d1i1m1o1n [39]

Answer:

magnitude of net magnetic field at given point is

$B = 5 \times 10^{-6} T$

Explanation:

As we know that magnetic field due to a long current carrying wire is given as

$B = \frac{\mu_o i}{2\pi r}$

here we we will find the magnetic field due to wire which is along x axis is given as

$i = 30 A$

r = 2 m

now we have

$B_1 = \frac{4\pi \times 10^{-7} (30)}{2\pi (2m)}$

$B_1 = 3\times 10^{-6} T$ into the plane

Now similarly magnetic field due to another wire which is perpendicular to xy plane is given as

$i = 40 A$

r = 2 m

now we have

$B_2 = \frac{4\pi \times 10^{-7} (40)}{2\pi (2m)}$

$B_2 = 4\times 10^{-6} T$ along + x direction

Since the two magnetic field is perpendicular to each other

So here net magnetic field is given as

$B = \sqrt{B_1^2 + B_2^2}$

$B = 5 \times 10^{-6} T$

5 0

3 years ago

Your lab instructor has asked you to measure a spring constant using a dynamic methodâ€”letting it oscillateâ€”rather than a sta

yuradex [85]

Answer:

k = 6,547 N / m

Explanation:

This laboratory experiment is a simple harmonic motion experiment, where the angular velocity of the oscillation is

w = √ (k / m)

angular velocity and rel period are related

w = 2π / T

substitution

T = 2π √(m / K)

in Experimental measurements give us the following data

m (g) A (cm) t (s) T (s)

100 6.5 7.8 0.78

150 5.5 9.8 0.98

200 6.0 10.9 1.09

250 3.5 12.4 1.24

we look for the period that is the time it takes to give a series of oscillations, the results are in the last column

T = t / 10

To find the spring constant we linearize the equation

T² = (4π²/K) m

therefore we see that if we make a graph of T² against the mass, we obtain a line, whose slope is

m ’= 4π² / k

where m’ is the slope

k = 4π² / m'

the equation of the line of the attached graph is

T² = 0.00603 m + 0.0183

therefore the slope

m ’= 0.00603 s²/g

we calculate

k = 4 π² / 0.00603

k = 6547 g / s²

we reduce the mass to the SI system

k = 6547 g / s² (1kg / 1000 g)

k = 6,547 kg / s² =

k = 6,547 N / m

let's reduce the uniqueness

[N / m] = [(kg m / s²) m] = [kg / s²]

7 0

2 years ago