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erica [24]
1 year ago
13

A 1.0 kg ball and a 2.0 kg ball are connected by a 1.1-m-long rigid, massless rod. The rod is rotating cw about its center of ma

ss at 19 rpm. What torque will bring the balls to a halt in 5.0 s?
Physics
1 answer:
katen-ka-za [31]1 year ago
7 0

The torque that will bring the balls to halt, t = 0.34 Nm

What is rotating?

In physics and mechanics, torque is the rotational equivalent of linear force. It is also referred to as the moment, moment of force, rotational force, or turning effect, depending on the field of study. It represents the capability of a force to produce a change in the rotational motion of the body.

Center of Mass of Rod = (1 * 0 + 2.0 * 1.1) /(1.0 + 2.0)

Center of Mass of Rod = 0.73 m

ω  = 21 rpm

ω = 21 * (2*pi)/60 rad/s

ω = 2.2 rad/s

Time to bring Halt = 5.2 s

Angular De-acceleration = 2.2/5.2 rad/s^2

α  =  0.423 rad/s^2

We know,

torque = (moment of inertia) * (angular acceleration)

t = I * α

Where

I = m1*r1^2 + m2*r2^2

I = 1kg * (0.73)^2 + 2kg * (1.1-0.73)^2

I = 0.8067 kg*m^2

Substituting Values -

torque = 0.8067  Kg*m^2 * 0.423 rad/s^2

torque = 0.34 N*m

The torque that will bring the balls to halt, t = 0.34 Nm

To learn more about the torque the link is given below:

brainly.com/question/18883167?

#SPJ4

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\int\limits^2_1  \, dp +\int\limits^2_1 {(\frac{1}{2}ρV^{2} )} \, +ρ \int\limits^2_1 {(g_{0}-cz )} \,dz=0\\p_{1}^{2}+\frac{1}{2}ρ(V^{2})_{1}^{2}+ρg_{0}z_{1}^{2}-ρc(\frac{z^{2}}{2})_{1}^{2}=0\\p_{2}-p_{1}+\frac{1}{2}ρ(V^{2}_{2}-V^{2}_{1})+ρg_{0}(z_{2}-z_{1})-\frac{1}{2}ρc(z^{2}_{2}-z^{2}_{1})=0\\p+\frac{1}{2}ρV^{2}+ρg_{0}z-\frac{1}{2}ρcz^{2}=constant

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