We are given
V = 100 V
R = 500 Ω
C = 10^4 F
q(0) = 0
We are asked to find the charge q(t) of the RC capacitor.
To solve this, we use the formula:
q(t) = CV [1 - e^(-t/RC) ]
Substituting thet given values
q(t) = 10^4 (100) [1 - e^(-t/500(10^4) ]
q(t) = 1 x 20^6 [1 - e^(-2x10^7 t) ]
Since we only asked to get the charge q(t) in terms of t, the answer is
q(t) = 1 x 20^6 [1 - e^(-2x10^7 t) ]
When a rock is pick up and thrown it's showing potential energy
Observations are used to record the results of an experiment.
<span>The answer is (2) 0.50 Hz. The frequency (f) of oscillation is the number of oscillations (n) per time (t) in seconds: f = n/t. A duck floating on a lake oscillates up and down 5.0 times (n = 5.0) during a 10.-second interval (t = 10.0 s). So, the frequency of duck's oscillations is: f = 5.0/10.0 s = 0.50 1/s = 0.50 Hz.Hope I helped! :) Cheers!</span>
