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Kazeer [188]
3 years ago
15

If a sample of a(

Physics
1 answer:
Otrada [13]3 years ago
7 0
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How does the mass of an object affect the outcome when an unbalanced force acts on it?
Verdich [7]

Answer:

The magnitude of acceleration is reduced.

Explanation:

Force is defined as push or pull

The force is said to be<em> balance force  </em>if the force are equal in size but opposite in direction. ie the object does not move or move with constant speed.

The force are to be<em> unbalanced force </em>if the force cause change in motion. ie the object has force greater than zero and has acceleration.

According to <em>Newton second law of motion </em>, acceleration depends on force acting on the object and mass of object.

     F=ma

     a=\frac{F}{m}

When unbalanced force act on the mass of object it reduces magnitude of acceleration without changing the direction.

6 0
3 years ago
An object is projected with initial speed v0 from the edge of the roof of a building that has height H. The initial velocity of
Vsevolod [243]

Answer:

Explanation:

Initial velocity u = V₀ in upward direction so it will be negative

u = - V₀

Displacement s = H . It is downwards so it will be positive

Acceleration = g ( positive as it is also downwards )

Using the formula

v² = u² + 2 g s

v² = (- V₀ )² + 2 g H

= V₀² + 2 g H .

v = √ ( V₀² + 2 g H )

6 0
3 years ago
What is the amount of heat required to raise the temperature of 200.0 g of aluminum by 10 c?
mash [69]
Q = 175.8J = 1.8• 10 2 J
5 0
3 years ago
A college dorm room measures 14 ft wide by 13 ft long by 6 ft high. What is the air in it under normal conditions?
kirza4 [7]

Complete question:

A college dormitory room measures 14 ft wide by 13 ft long by 6 ft high. Weight density of air is 0.07 lbs/ft3. What is the weight of air in it under normal conditions?

Answer:

the weight of the air is 76.44 lbs

Explanation:

Given;

dimension of the dormitory, = 14 ft by 13 ft by 6 ft

density of the air, = 0.07 lbs/ft³

The volume of the air in the dormitory room = 14 ft x 13 ft x 6 ft

                                                                          = 1092 ft³

The weight of the air = density  x  volume

                                   = 0.07 lbs/ft³  x  1092 ft³

                                   = 76.44 lbs

Therefore, the weight of the air is 76.44 lbs

6 0
2 years ago
Physics!!! please help D:
Ugo [173]
Answer: A

Explanation: isotopes of the same thing element have the same number of protons in the nucleus but differ in the number of neutrons.
6 0
2 years ago
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