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Kazeer [188]
4 years ago
15

If a sample of a(

Physics
1 answer:
Otrada [13]4 years ago
7 0
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Yellow light travels through a certain glass block at a speed of 1.97 × 108 m/s. The wavelength of the light in this particular
Andre45 [30]

The frequency of the yellow light is 5.17\cdot 10^{14}Hz

Explanation:

The relationship between wavelength, frequency and speed of a wave is given by the wave equation:

v = f \lambda

where

v is the speed of the wave

f is the frequency

\lambda is the wavelength

For the yellow light in this problem, we have:

v=1.97\cdot 10^8 m/s is the speed

\lambda=3.81\cdot 10^{-7} m is the wavelength

Solving for f, we find its frequency:

f=\frac{v}{\lambda}=\frac{1.97\cdot 10^8}{3.81\cdot 10^{-7}}=5.17\cdot 10^{14}Hz

Learn more about frequency and waves:

brainly.com/question/5354733

brainly.com/question/9077368

#LearnwithBrainly

8 0
3 years ago
Construct a process by which rocks may change form
love history [14]
<span>Crystallization, metamorphism, and erosion and sedimentation.<span>Any rock can transform into another rock by passing through one or more of these processes. 
Hope it helps :)</span></span>
5 0
3 years ago
You set a small eraser at a distance of 0.27 m from the center of a turntable you find in the attic and establish that when the
Licemer1 [7]

Answer with Explanation:

We are given that

Distance,r=0.27 m

Tangential speed=v=0.49 m/s

a.Angular speed ,\omega=\frac{v}{r}

Using the formula

\omega=\frac{0.49}{0.27}=1.8 rad/s

\omega=\frac{2\pi}{T}

T=\frac{2\pi}{\omega}

Time period,T=\frac{2\pi}{1.8}=3.49 s

b.Amplitude,A=Distance of small eraser from the center of a turnable =0.27 m

c.Maximum speed,V_{max}=0.49 m/s

d.Maximum acceleration=a=r\omega^2=0.27(1.8)^2=0.87 m/s^2

5 0
4 years ago
Read 2 more answers
John is going to use a rope to pull his sister Laura across the ground in a sled through the snow. The rope makes an angle of 25
Liula [17]
The mass of Laura and the sled combined is 887.5 kg
5 0
3 years ago
A ball is thrown upward from the top of a building at an angle of 30.0° to the horizontal and with
Ray Of Light [21]

Answer:

See below

Explanation:

Vertical position = 45 +  20 sin (30) t  - 4.9 t^2

 when it hits ground this = 0

               0 = -4.9t^2 + 20 sin (30 ) t + 45

                0 = -4.9t^2 + 10 t +45 = 0     solve for t =4.22 sec

  max height is at  t= - b/2a = 10/9.8 =1.02

     use this value of 't' in the equation to calculate max height = 50.1 m

      it has  4.22 - 1.02 to free fall = 3.2 seconds free fall

           v = at = 9.81 * 3.2 = 31.39 m/s VERTICAL

      it will <u>also</u> still have horizontal velocity =  20 cos 30 = 17.32 m/s

        total velocity will be sqrt ( 31.39^2 + 17.32^2) = 35.85 m/s

Horizontal range = 20 cos 30  * t  =  20 *  cos 30  * 4.22 = 73.1 m

8 0
2 years ago
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