Doubling the radius of the cylinder will quadruple the volume.
Answer:
x > -1 or x < -1
Step-by-step explanation:
For the first equation, 5x-29 > -3
Step 1: Move the constant to the right and change its sign
5x-29 > -34
5x > -34+29
Step 2: Calculate the sum
5x > -34+29
5x > -5
Step 3: Divide both sides of the inequality by <em>5</em>
5x > -5
x > -1
<em><u>Answer</u></em><em><u>:</u></em> -1
For the second equation, 2x+31 < 29
Step 1: Move constant to the right and change its sign
2x+31 < 29
2x < 29-31
Step 2: Calculate the difference
2x < 29-31
2x < -2
Step 3: Divide both sides of the inequality by 2
2x < -2
x < -1
<em><u>Answer</u></em><em><u>:</u></em> x < -1
Answer:
11/2??????
Step-by-step explanation:
Answers:
10.) 
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Step-by-step explanations:
10.) 
9.) ![\displaystyle \frac{\sqrt[3]{135}}{\sqrt[3]{40}} \hookrightarrow \sqrt[3]{3\frac{3}{8}} \hookrightarrow \frac{3\sqrt[3]{5}}{2\sqrt[3]{5}} \\ \\ \boxed{1\frac{1}{2}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B%5Csqrt%5B3%5D%7B135%7D%7D%7B%5Csqrt%5B3%5D%7B40%7D%7D%20%5Chookrightarrow%20%5Csqrt%5B3%5D%7B3%5Cfrac%7B3%7D%7B8%7D%7D%20%5Chookrightarrow%20%5Cfrac%7B3%5Csqrt%5B3%5D%7B5%7D%7D%7B2%5Csqrt%5B3%5D%7B5%7D%7D%20%5C%5C%20%5C%5C%20%5Cboxed%7B1%5Cfrac%7B1%7D%7B2%7D%7D)
8.) ![\displaystyle \frac{\sqrt[4]{162}}{\sqrt[4]{32}} \hookrightarrow \sqrt[4]{5\frac{1}{16}} \hookrightarrow \frac{\pm{3\sqrt[4]{2}}}{\pm{2\sqrt[4]{2}}} \\ \\ \boxed{\pm{1\frac{1}{2}}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B%5Csqrt%5B4%5D%7B162%7D%7D%7B%5Csqrt%5B4%5D%7B32%7D%7D%20%5Chookrightarrow%20%5Csqrt%5B4%5D%7B5%5Cfrac%7B1%7D%7B16%7D%7D%20%5Chookrightarrow%20%5Cfrac%7B%5Cpm%7B3%5Csqrt%5B4%5D%7B2%7D%7D%7D%7B%5Cpm%7B2%5Csqrt%5B4%5D%7B2%7D%7D%7D%20%5C%5C%20%5C%5C%20%5Cboxed%7B%5Cpm%7B1%5Cfrac%7B1%7D%7B2%7D%7D%7D)
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I am joyous to assist you at any time.
