log10 1000 = 3 or log 1000 = 3
<span>Mixed numbers from 6 to 7 with an interval of 1/5 between each pair of mixed numbers are {6 1/5, 6 2/5, 6 3/5, 6 4/5}</span>
<span>Ishaan is 21, Christopher is 7
No actual question given, but I will assume that the question is "How old are they?". If that's the case, we can create two equations. I'll use I for Ishaan's age and C for Christopher's. I will also assume that there's been some formatting issues here and for some reason, numbers are repeated 3 times without any spaces. So
"Ishaan is 3 times as old as Christopher"
I = 3C
"is also 14 years older than Christopher
I = C + 14
Since both equations are equal to each other, let's set them equal. So
3C = C + 14
2C = 14
C = 7
So Christopher is 7. And we can use the equation I = C + 14 to get Ishaan's age. So
I = C + 14
I = 7 + 14
I = 21</span>
Answer:
A. 11
Step-by-step explanation:
11-3=9
The set does not include 9 because the sign is not underlined so 11 is not a solution.
