A 6.00-m long string sustains a three-loop standing wave pattern as shown. The wave speed is 2.00 × 102 m/s.What is the lowest p
ossible frequency for standing waves on this string?
1 answer:
Given:
The length of the string is l = 6 m
The speed of the wave is
Required: Lowest possible frequency for the standing wave.
Explanation:
The lowest possible frequency is the fundamental frequency.
The fundamental frequency can be calculated by the formula
On substituting the values, the fundamental frequency will be
Final Answer: The lowest possible frequency for standing waves on this string is 16.67 Hz
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the maximum vertical height the person in the cart can reach is 18.42 m
Explanation:
Given;
mass of the person in cart, m₁ = 45 kg
mass of the cart, m₂ = 43 kg
acceleration due to gravity, g = 9.8 m/s²
final speed of the cart before it goes up the hill, v = 19 m/s
Apply the principle of conservation of energy;
Therefore, the maximum vertical height the person in the cart can reach is 18.42 m
Answer:
The acceleration of the proton is 1.403 x 10⁹ m/s²
Explanation:
Given;
speed of proton, v = 7.7 m/s
magnitude of magnetic field, B = 1.9 T
Magnetic force of moving proton is given by;
F = qvBsinθ
Centripetal force on the moving proton is given by;
where;
q is charge of the proton = 1.602 x 10⁻¹⁹ C
m is mass of proton = 1.67 x 10⁻²⁷ kg
Therefore, the acceleration of the proton is 1.403 x 10⁹ m/s²