Upward force provided by the branch is 260 N
<u>Explanation:</u>
Given -
Mass of Gibbon, m = 9.3 kg
Length of the branch, r = 0.6 m
Speed of the movement, v = 3.3 m/s
Upward force, T = ?
The tension force in the rod must be greater than the weight at the bottom of the swing in order to provide an upward centripetal acceleration.
Therefore,
F net = T - mg
F net = ma = mv²/r
Thus,
T = mv²/r + mg
T = m ( v²/r + g)
T = 9.3 [ ( 3.3)² / 0.6 + 9.8]
T = 259.9 N ≈ 260 N
Therefore, upward force provided by the branch is 260 N
Answer:
The associated SI unit of force and weight is the Newton, with 1 kilogram weighing 9.8 Newtons under standard conditions on the Earth's surface. However, in the US common units, the pound is the unit of force (and therefore weight). The pound is the widely used unit for commerce.
Answer:
a) total moment of inertia is 1359.05 kg m^2
b) angular acceleratio is 0.854rad/sec^2
Explanation:
Given data:
m1=6.9 kg
L=4.88 m
m2=34.5 kg
R=1.22 m
we klnow that moment of inertia for rod is given as
J1=(1/12) ×m×L^2

moment of inertia for sphere is given as
J1=(2/5) ×m×r^2

As object rotates around free end of rod then for sphere the axis around what it rotates is at a distance of d2=L+R
For rod distance is d1=0.5*L
By Steiner theorem
for the rod we get 

for the sphere we get 

And the total moment of inertia for the first case is

b) F=476 N
The torque for system is given as

where a is angle between Force and distance d
and where d represent distance from rotating axis.
In this case a = 90 degree

M=476*2.44 = 1161.44 Nm
The acceleration is calculated as

= 0.854 rad/sec^2
Answer:
Explanation:
See the attached figure . See the forces acting on man pulling up the box .
Man is stationary so net force acting on man is zero .
T + R = Wman
R is the reaction force of the ground of second floor .
R = Wman - T