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ivolga24 [154]
3 years ago
7

The electric potential difference of a 125 F capacitor is measured across the terminals of the capacitor and found to be 9.0 V.

The potential energy of the capacitor, rounded to two significant figures, is
Physics
1 answer:
Marrrta [24]3 years ago
7 0

Answer:

E=1/2CV^2

where E is potential energy, C is capacitance and V is the voltage.

E=1/2×125×9^2

E=1/2×125×81

E=5062.5

E=5100J to 2 significant figures.

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