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Fiesta28 [93]
4 years ago
13

Tamika inflates and ties off a balloon in her classroom and then takes it outside on a cold, winter day. Immediately, she notice

s that the balloon has gotten a little bit smaller. Why does this occur?
A) because there are fewer molecules in the balloon outside
B) because the air pressure is significantly higher when it is colder
C) because the molecules in the balloon have slowed down with the temperature
D) because the molecules shrink in size when exposed to the colder, outside air
Physics
2 answers:
Annette [7]4 years ago
7 0

Answer: Option (C) is the correct answer.

Explanation:

When the balloon was placed inside Tamika's classroom then the temperature was high as compared to the temperature outside the classroom.

As a result, gas molecules were in rapid motion but when balloon was placed outside the classroom then due to cold, there was decrease in temperature.

Therefore, the movement of gas molecules will slow down and the molecules will come slightly close to each other.

Hence, there will be shrinkage in the size of balloon.

Thus, we can conclude that the balloon has gotten a little bit smaller because the molecules in the balloon have slowed down with the temperature.

stealth61 [152]4 years ago
3 0
The balloon has gotten a little bit smaller C) because the molecules in the balloon have slowed down with the temperature.
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7 0
3 years ago
A vertical spring (ignore its mass), whose spring stiffness constant is 880 n/m, is attached to a table and is compressed down 0
sladkih [1.3K]
When the spring is compressed, the potential energy stored in the spring is:
U= \frac{1}{2}kx^2
where k=880 N/m is the spring constant and x=0.170 m is the compression of the spring. By using these numbers, we get
U= \frac{1}{2}(880 N/m)(0.170 m)^2=12.7 J

When the spring is released with the ball over it, all the potential energy is converted into kinetic energy of the ball:
U=K= \frac{1}{2} mv^2
So by using m=0.300 kg, and re-arranging the formula, we can calculate the velocity of the ball:
v= \sqrt{ \frac{2K}{m} }= \sqrt{ \frac{2\cdot 12.7 J}{0.300 kg} }=9.2 m/s
5 0
3 years ago
What type of stars will potentially one day
xz_007 [3.2K]

Answer:

2, High mass stars.

Add-on:

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4 0
2 years ago
A refrigerator has a coefficient of performance equal to 4.00. The refrigerator takes in 110 J of energy from a cold reservoir i
Helga [31]

Answer:

The correct answer is:

(a) 27.5 Joules

(b) 141.5 Joules

Explanation:

Given:

Energy,

Q_c = 110 \ J

Coefficient of performance refrigerator,

Cop(refrig)=4

(a)

As we know,

⇒ Cop(refrig) = \frac{Q_c}{Work}

or,

⇒ Work=\frac{Q_c}{Cop(refrig)}

              =\frac{110}{4}

              =27.5 \ Joules

(b)

⇒ Heat \ expelled = Heat \ removed +Work \ done

or,

⇒ Q_h = Q_c+Work

         =114+27.5

         =141.5 \ Joules

4 0
3 years ago
If you run east for 38m, stop suddenly, run another 27m east, then you run west for 47
AysviL [449]

Answer:

Total Displacement = -18m

Explanation:

Given

East Movement = 38m and 27m

West Movement = 47m

Required

Determine the total displacement

To answer this, we consider east as negative direction and the west as positive (using logics of number line).

Total Displacement = East Movement + West Movement

Total Displacement = -38m - 27m + 47m

Total Displacement = -18m

Hence, the total displacement is 18m towards East

6 0
3 years ago
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