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Stels [109]
3 years ago
15

Find the lateral surface area below given prism:

Mathematics
1 answer:
Firdavs [7]3 years ago
8 0

Answer:

the answer should be 158 but I'm not a hundred percent sure

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PLEASE HELP
Fed [463]

Answer:

Hi how are you doing today Jasmine

7 0
3 years ago
What is seven over twenty one take away one over twenty one in its simplest form
natulia [17]
It would be 6/21 but simplified it would be 2/7
5 0
3 years ago
Round 6.85565 to the nearest tenth !
emmasim [6.3K]

Answer:

It is 6.9

Step-by-step explanation:

6.85565

put

6.85

5 can be rounded up so

6.9 is answer

3 0
4 years ago
What is x when 44x=78
pantera1 [17]
X= 1.77
Hope this helps :)
3 0
3 years ago
Read 2 more answers
Which expression is equivalent?
babymother [125]

Answer:

Third choice from the top is the one you want

Step-by-step explanation:

This whole concept relies on the fact that if the index of a radical exactly matches the power under the radical, both the radical and the power cancel each other out.  For example:

\sqrt[6]{x^6} =x and another example:

\sqrt[12]{2^{12}}=2

Let's take this step by step.  First we will rewrite both the numerator and the denominator in rational exponential equivalencies:

\frac{\sqrt[4]{6} }{\sqrt[3]{2} }=\frac{6^{\frac{1}{4} }}{2^{\frac{1}{3} }}

In order to do anything with this, we need to make the index (ie. the denominators of each of those rational exponents) the same number.  The LCM of 3 and 4 is 12.  So we rewrite as

\frac{6^{\frac{3}{12} }}{2^{\frac{4}{12} }}

Now we will put it back into radical form so we can rationalize the denominator:

\frac{\sqrt[12]{6^3} }{\sqrt[12]{2^4} }

In order to rationalize the denominator, we need the power on the 2 to be a 12.  Right now it's a 4, so we are "missing" 8.  The rule for multiplying like bases is that you add the exponents.  Therefore,

2^4*2^8=2^{12}

We will rationalize by multiplying in a unit multiplier equal to 1 in the form of

\frac{\sqrt[12]{2^8} }{\sqrt[12]{2^8} }

That looks like this:

\frac{\sqrt[12]{6^3} }{\sqrt[12]{2^4} }*\frac{\sqrt[12]{2^8} }{\sqrt[12]{2^8} }

This simplifies down to

\frac{\sqrt[12]{216*256} }{\sqrt[12]{2^{12}} }

Since the index and the power on the 2 are both 12, they cancel each other out leaving us with just a 2!  Doing the multiplication of those 2 numbers in the numerator gives us, as a final answer:

\frac{\sqrt[12]{55296} }{2}

Phew!!!

4 0
4 years ago
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