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Vladimir [108]
10 months ago
9

(a) what is the period of small oscillations for this pendulum if it is located in an elevator accelerating upward at 9.00 m/s2?

Physics
1 answer:
Vinvika [58]10 months ago
7 0

If this pendulum is situated in an elevator that is moving upward at a speed of 9.00 m/s2, the period of its minor oscillations is 4.34s.

<h3>One oscillation is it a period?</h3>

Period is equal to the length of one oscillation.

T. T . The frequency is the number of oscillations that occur in one second.

<h3>Short answer: How long does a pendulum swing?</h3>

A simple pendulum's period is: The symbol "T" stands for the period of time needed by the pendulum to complete one complete oscillation. The length of a basic pendulum: It is described as the distance the pendulum moves away from equilibrium and toward one side.

Since the elevator's oscillations for this pendulum are situated there and it is climbing at a 9.0 mph,

use G = 9.8 + 9.0 = 18.8 m/s²

Period T=2π√(L/G)

T= 2π√(9/18.8)

T=4.34s

To know more about oscillation visit:-

brainly.com/question/29273618

#SPJ4

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How much time will it take to perform 440 joule of work at a rare of 11 w?​
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40sec

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2 years ago
Suppose two point charges, Q1 = -6.25 x 10-9 C and Q2 = -6.25 x 10-9 C, are separated by a distance d = 0.617 m.
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Answer:

The answer to your question is the letter A) F =  9.23 x 10⁻⁷ N

Explanation:

Data

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q₂ = -6.25 x 10⁻⁹ C

d = 0.617 m

k = 9 x 10⁹ Nm²/C²

F = ?

Formula

              F = k q₁q₂ /r²

-Substitution

              F = (9 x 10⁹)(-6.25 x 10⁻⁹)(-6.25 x 10⁻⁹) / (0.617)²

-Simplification

              F = 3.512 x 10⁻⁷ / 0.381

-Result

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