The option is Work.
The product of charge and potential is equal to the energy. Adn, as we know work is related to energy as the capacity to do work.
Alos, because, Potential is given as, V = E/q
or E = Vq
Thus, t<span>he product of charge through, and potential across, an electrical device is:work
</span>
Answer:
See the answers below
Explanation:
To solve this problem we must use the following equation of kinematics.
where:
Vf = final velocity [m/s]
Vo = initial velocity [m/s]
a = acceleration [m/s²]
t = time [s]
<u>First case</u>
Vf = 6 [m/s]
Vo = 2 [m/s]
t = 2 [s]
<u>Second case</u>
Vf = 25 [m/s]
Vo = 5 [m/s]
a = 2 [m/s²]
<u>Third case</u>
Vo =4 [m/s]
a = 10 [m/s²]
t = 2 [s]
<u>Fourth Case</u>
Vf = final velocity [m/s]
Vo = initial velocity [m/s]
a = acceleration [m/s²]
t = time [s]
<u>Fifth case</u>
Vf = final velocity [m/s]
Vo = initial velocity [m/s]
a = acceleration [m/s²]
t = time [s]
Answer:
<em>The answer is medial!</em>
Explanation:
<em>The vertebral region is </em><u><em>medial</em></u><em> to the scapula.</em>
<em>Hope This Helps!</em>
<em>-</em><u><em>Justin:)</em></u>
To solve the problem it is necessary to apply conservation of the moment and conservation of energy.
By conservation of the moment we know that
Where
M=Heavier mass
V = Velocity of heavier mass
m = lighter mass
v = velocity of lighter mass
That equation in function of the velocity of heavier mass is
Also we have that
On the other hand we have from law of conservation of energy that
Where,
W_f = Work made by friction
KE = Kinetic Force
Applying this equation in heavier object.
Here we can apply the law of conservation of energy for light mass, then
Replacing the value of
Deleting constants,
Calorimetry :
<em><u>the process of measuring the amount of heat released or absorbed during a chemical reaction</u></em>.
Calorimeter :
<em><u>device for measuring the heat developed during a mechanical, electrical, or chemical reaction, and for calculating the heat capacity of materials</u></em>.