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steposvetlana [31]
3 years ago
8

A bowling ball has a mass of 5 kg. What happens to its momentum when the speed increases from 1 m/s to 2 m/s?

Physics
2 answers:
Leto [7]3 years ago
7 0

The correct answer of this question is : D) The initial momentum is 5 kg m/s, and the final momentum is 10 kg m/s

EXPLANATION :

Before going to answer this question, first we have to understand the momentum.

The momentum of a body is the amount of motion contained in a body. Quantitatively momentum is the product of mass with velocity.

Mathematically momentum p = mv.

Here, m is the mass of the body, and v is the velocity of the body.

As per the question, the mass of the ball m = 5 Kg.

The initial velocity of the ball u = 1 m/s.

Hence, initial momentum = m × u

                                          = 5 Kg × 1 m/s

                                          = 5 Kg.m/s

The final velocity of the ball v = 2 m/s

Hence, final momentum p = m × v

                                            = 5 Kg × 2 m/s

                                            = 10 Kg.m/s                        [ans]


Alona [7]3 years ago
5 0
<span>The initial momentum is 5 kg m/s and the final momentum is 10 kg m/s

'cause P = m*v, when we increase either m or v, P also increases by the same expression, 

P = 5 * 2 = 10

So, option D is your answer!!

Hope this helps!

</span>
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3 years ago
At a playground, a child slides down a slide that makes a 42° angle with the horizontal direction. The coefficient of kinetic fr
kumpel [21]

Answer:

a = 5.1\ m/s^2

Explanation:

Given,

The angle of the slide=42^\circ

The mass of the child is= m

coefficient of friction = 0.20

when she slides down now apply Newton's law

ma =mg \sin\theta - f

ma = mg\sin \theta -\mu mg \cos \theta

therefore the acceleration

a=g \sin\theta -\mu gcos\theta

a=g[\sin \theta -\mu \cos \theta]

a=9.8\times [\sin 42^\circ -0.2\times \cos 42^\circ]

a = 5.1\ m/s^2

hence, the magnitude of acceleration during her sliding is equal to  a = 5.1\ m/s^2

4 0
3 years ago
2. What is the mass of an object that has 50000 J
muminat

Answer:

m= 666.67 or 667

Explanation:

KE= 50000 J

v= 75 m/s

m= ?

M= 50000 / 75

m= 666.67  or 667

3 0
2 years ago
A solid Cute hug sides 0.50m
irina [24]

Answer:

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Explanation:

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3 0
3 years ago
Some of the highest tides in the world occur in the Bay of Fundy on the Atlantic Coast of Canada. At Hopewell Cape the water dep
Nady [450]

Answer:

(a) 1.939 m/h

(b) 0.926 m/h

(c) -0.315 m/h

(d) -1.21 m/h

Explanation:

Here, we have the water depth given by the function of time;

D(t) = 7 + 5·cos[0.503(t-6.75)]

Therefore, to find the velocity of the depth displacement with time, we differentiate the given expression with respect to time as follows;

D'(t) = \frac{d(7 + 5\cdot cos[0.503(t-6.75)])}{dt}

= 5×(-sin(0.503(t-6.75))×0.503

= -2.515×(-sin(0.503(t-6.75))

= -2.515×(-sin(0.503×t-3.395))

Therefore we have;

(a) at 5:00 AM = 5 -  0:00 = 5

D'(5) =  -2.515×(-sin(0.503×5-3.395)) = 1.939 m/h

(b) at 6:00 AM = 6 -  0:00 = 6

D'(5) =  -2.515×(-sin(0.503×6-3.395)) = 0.926 m/h

(c) at 7:00 AM = 7 -  0:00 = 7

D'(5) =  -2.515×(-sin(0.503×7-3.395)) = -0.315 m/h

(d) at Noon 12:00 PM = 12 -  0:00 = 12

D'(5) =  -2.515×(-sin(0.503×12-3.395)) = -1.21 m/h.

4 0
2 years ago
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