There’s literally no question here
Answer:
Yellow reflects most of the light and thus draws lots of attention; too bright a shade will leave you irritated. Prolonged exposure can also have a tiring effect. It is best used in down-tones; as background for white articles/figures. Green is the color of tranquility and vibrant.
Explanation:
Answer:
Indexical Signs
Explanation:
According to Charles Peirce, when there is "existential" relationship that exist between the sign and interpretant, then indexical signs are involved. This implies that at some point in time, they have existed at the same time or in the same place. One indexical sign of a human being is Fingerprints. However, photographs are classified as indexical signs testifying that at some moment, the camera was present.
Answer:
Explanation:
We could get the four options for this particular example, but we must know what happens with the variable number the value 1000.
In this case, we are going to assume four scenarios:
1) n = n - n this is equal to 0
2) n = (n - n) + n = 1000
3) n = n * 2 = 2000
4) n = n * 3 = 3000
These are simple examples, we could get these options in different ways.
Answer:
The program in C++ is as follows:
#include <iostream>
using namespace std;
void display(int array_test [], int n){
for(int i = 0; i<n;i++){
cout<<array_test[i]<<" "; }
}
int main(){
int n;
cin>>n;
int array_test[n];
for(int i = 0; i<n;i++){
cin>>array_test[i];
}
display(array_test,n);
return 0;
}
Explanation:
This defines the display function
void display(int array_test [], int n){
This iterates through the array
for(int i = 0; i<n;i++){
This prints each element of the array
cout<<array_test[i]<<" "; }
}
The main begins here
int main(){
This declares n as integer; n represents the length of the array
int n;
This gets input for n
cin>>n;
This declares the array
int array_test[n];
The following iteration gets input for the array
for(int i = 0; i<n;i++){
cin>>array_test[i];
}
This calls the display function to display the elements of the array
display(array_test,n);
return 0;
}