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Licemer1 [7]
4 years ago
12

It is harder to stop a rolling bowling ball than a rolling ping pong ball when both are rolling at the same velocity. Which is t

his an example of?
a. inertia
b. momentum
c. balanced force
Physics
2 answers:
Evgen [1.6K]4 years ago
6 0
I believe it might be inertia
zepelin [54]4 years ago
5 0
<span> it is the example of momentum because bowling ball has more mass and therefore more momentum behind it.
                                                         hope its help</span>
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What is the definition for relative motion
xeze [42]
Relative motion is the calculation of the motion of an object with regard to some other moving object.
7 0
3 years ago
A tiger runs one kilometer. The tiger does 15,000 J of work and has a total power output of 500 W. How many minutes does it take
defon
Power is the amount of energy consumed per unit time. Having no direction, it is a scalar quantity. <span>As is implied by the equation for </span>power<span>, a unit of </span>power <span>is equivalent to a unit of work divided by a unit of time. The formula would be as follows:

P = W/t 

We calculate as follows:

500 W = 15000 J / t
t = 30 s</span>
3 0
3 years ago
Analyze how friction can be both a positive and negative aspect on our lives
denpristay [2]
Positive - Friction allows us to create heat in a desperate situation, like being lost in the woods. If we didn't have friction, we would probably freeze to death.
Negative - Friction can also cause unwanted fires, such as forest fires. If friction didn't exist, we wouldn't have these.
8 0
4 years ago
Heat is extracted from a certain quantity of steam at
vodomira [7]

Answer:v=2452.91 m/s

Explanation:

Given

initially steam is at 100^{\circ}C and converted to 0^{\circ} C ice

Let m be the mass of steam

latent heat of fusion and vaporization for water is

L_f=3.33\times 10^5 J/kg

L_v=2.26\times 10^6 J/kg

Heat required to convert steam in to water at 100^{\circ}C

Q_1=m\times L_v=m\cdot 2.26\times 10^6 J

Heat required to lower water temperature to 0^{\circ}C

Q_2=m\times c\times \Delta T

Q_2=m\times 4.184\times (100)

Q_2=4.184m\times 10^5 J

Heat required to convert 0^{\circ}C water to ice at 0^{\circ}C is

Q_3=m\times L_f

Q_3=m\times 3.33\times 10^5=3.33m\times 10^5 J

Q=Q_1+Q_2+Q_3

Q=(2.26+0.4184+0.33)m\times 10^6 J

Q=3.0084m\times 10^6 J

So this energy is equal to kinetic energy of  bullet of mass m moving with velocity v

Q=\frac{1}{2}mv^2

3.0084m\times 10^6=\frac{1}{2}mv^2

v^2=3.0084\times 2\times 10^6

v=2.452\times 10^3 m/s

v=2452.91 m/s  

5 0
4 years ago
Which is NOT part of the equation for angular momentum?
Solnce55 [7]
For the answer to the question above asking <span>Which is NOT part of the equation for angular momentum? The answer is the last one among the given choices above which is D. Force
I hope my answer helped you. Have a nice day!</span>
8 0
3 years ago
Read 2 more answers
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